回答編集履歴

1

追記

2018/04/10 09:27

投稿

yambejp
yambejp

スコア114883

test CHANGED
@@ -83,3 +83,123 @@
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  having name='aaaa' and q1='y'
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  ```
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+
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+ # 追記
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+
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+ - なんか変なので書き直し
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+ ```SQL
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+ select name,q,yn,count(*) as count
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+ ,count(*)/(select count(*) from `check` as t2 where t1.name=t2.name) as ratio
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+
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+ from (
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+ select name,'q1' as q,q1 as yn from `check`
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+ union all select name,'q2',q2 from `check`
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+ union all select name,'q3',q3 from `check`
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+ union all select name,'q4',q4 from `check`
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+ ) as t1
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+ group by name,q,yn
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+
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+ ```
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+ - 上記集計して
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+ ```SQL
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+ select name
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+
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+ ,yn
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+
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+ ,sum((q='q1')* ratio) as q1
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+
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+ ,sum((q='q2')* ratio) as q2
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+
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+ ,sum((q='q3')* ratio) as q3
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+
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+ ,sum((q='q4')* ratio) as q4
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+
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+ from(
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+
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+ select name,q,yn,count(*) as count
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+
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+ ,count(*)/(select count(*) from `check` as t2 where t1.name=t2.name) as ratio
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+ from (
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+ select name,'q1' as q,q1 as yn from `check`
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+ union all select name,'q2',q2 from `check`
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+ union all select name,'q3',q3 from `check`
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+ union all select name,'q4',q4 from `check`
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+ ) as t1
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+
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+ group by name,q,yn
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+
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+ ) as t3
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+ group by name,yn
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+
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+ ```
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+ - havingで条件をつけて抽出
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+ ```SQL
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+ select name
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+
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+ ,yn
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+
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+ ,sum((q='q1')* ratio) as q1
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+
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+ ,sum((q='q2')* ratio) as q2
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+
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+ ,sum((q='q3')* ratio) as q3
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+
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+ ,sum((q='q4')* ratio) as q4
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+
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+ from(
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+
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+ select name,q,yn,count(*) as count
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+
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+ ,count(*)/(select count(*) from `check` as t2 where t1.name=t2.name) as ratio
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+
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+ from (
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+
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+ select name,'q1' as q,q1 as yn from `check`
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+
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+ union all select name,'q2',q2 from `check`
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+
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+ union all select name,'q3',q3 from `check`
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+
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+ union all select name,'q4',q4 from `check`
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+
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+ ) as t1
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+
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+ group by name,q,yn
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+
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+ ) as t3
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+
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+ group by name,yn
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+
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+ having name='aaaa' and yn='y'
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+ ```