回答編集履歴
5
修正
answer
CHANGED
@@ -1,10 +1,10 @@
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1
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もう少し簡略化できそうな気もしますが、取り敢えずこんな感じでしょうか。
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```SQL
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select `name`
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4
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-
, (
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4
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, (q1y/cnt) * 100 as q1y_per
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-
, (
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5
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, (q2y/cnt) * 100 as q2y_per
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-
, (
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6
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, (q3y/cnt) * 100 as q3y_per
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-
, (
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, (q4y/cnt) * 100 as q4y_per
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from (
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select `name`
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, sum(case when q1='y' then 1 else 0 end) as q1y
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@@ -21,10 +21,10 @@
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boolean型を数値として扱って簡略化すると
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```SQL
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select `name`
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-
, (
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, (q1y/cnt) * 100 as q1y_per
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-
, (
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+
, (q2y/cnt) * 100 as q2y_per
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-
, (
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+
, (q3y/cnt) * 100 as q3y_per
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-
, (
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, (q4y/cnt) * 100 as q4y_per
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from (
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select `name`
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, sum((q1='y')) as q1y
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@@ -39,10 +39,10 @@
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いっそまとめて
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```SQL
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select `name`
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-
,
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, sum((q1='y')) / count(*) * 100 as q1y_per
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-
,
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, sum((q2='y')) / count(*) * 100 as q2y_per
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-
,
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, sum((q3='y')) / count(*) * 100 as q3y_per
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-
,
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, sum((q4='y')) / count(*) * 100 as q4y_per
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from ckeck
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group by `name`
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```
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4
修正
answer
CHANGED
@@ -1,6 +1,6 @@
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1
1
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もう少し簡略化できそうな気もしますが、取り敢えずこんな感じでしょうか。
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2
2
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```SQL
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3
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-
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3
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+
select `name`
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, (cnt/q1y) * 100 as q1y_per
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, (cnt/q2y) * 100 as q2y_per
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, (cnt/q3y) * 100 as q3y_per
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@@ -20,7 +20,7 @@
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---
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boolean型を数値として扱って簡略化すると
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```SQL
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-
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+
select `name`
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, (cnt/q1y) * 100 as q1y_per
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, (cnt/q2y) * 100 as q2y_per
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, (cnt/q3y) * 100 as q3y_per
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@@ -38,7 +38,7 @@
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```
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39
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いっそまとめて
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40
40
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```SQL
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-
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+
select `name`
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, count(*) / sum((q1='y')) * 100 as q1y_per
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, count(*) / sum((q2='y')) * 100 as q2y_per
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, count(*) / sum((q3='y')) * 100 as q3y_per
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3
推敲
answer
CHANGED
@@ -39,10 +39,10 @@
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39
39
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いっそまとめて
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40
40
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```SQL
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slect `name`
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-
,
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42
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+
, count(*) / sum((q1='y')) * 100 as q1y_per
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43
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-
,
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+
, count(*) / sum((q2='y')) * 100 as q2y_per
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44
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-
,
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+
, count(*) / sum((q3='y')) * 100 as q3y_per
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45
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-
,
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, count(*) / sum((q4='y')) * 100 as q4y_per
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46
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from ckeck
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group by `name`
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```
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2
修正
answer
CHANGED
@@ -19,7 +19,6 @@
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追記
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---
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boolean型を数値として扱って簡略化すると
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-
```
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```SQL
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slect `name`
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, (cnt/q1y) * 100 as q1y_per
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1
追記
answer
CHANGED
@@ -15,4 +15,35 @@
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from ckeck
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group by `name`
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) clc
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+
```
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19
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+
追記
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+
---
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21
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+
boolean型を数値として扱って簡略化すると
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22
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+
```
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23
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+
```SQL
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24
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+
slect `name`
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25
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+
, (cnt/q1y) * 100 as q1y_per
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26
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+
, (cnt/q2y) * 100 as q2y_per
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27
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+
, (cnt/q3y) * 100 as q3y_per
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28
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+
, (cnt/q4y) * 100 as q4y_per
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from (
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select `name`
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, sum((q1='y')) as q1y
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, sum((q2='y')) as q2y
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, sum((q3='y')) as q3y
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, sum((q4='y')) as q4y
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35
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, count(*) as cnt
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from ckeck
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group by `name`
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) clc
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```
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40
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+
いっそまとめて
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41
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```SQL
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42
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slect `name`
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, cout(*)/ sum((q1='y')) * 100 as q1y_per
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44
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+
, cout(*)/ sum((q2='y')) * 100 as q2y_per
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45
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+
, cout(*)/ sum((q3='y')) * 100 as q3y_per
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46
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+
, cout(*)/ sum((q4='y')) * 100 as q4y_per
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47
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+
from ckeck
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48
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group by `name`
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18
49
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```
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