回答編集履歴
1
追記
answer
CHANGED
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@@ -18,4 +18,27 @@
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18
18
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preg_match($p2,$str,$matches[1]);
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19
19
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preg_match($p3,$str,$matches[2]);
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20
20
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print $str.":".(count(array_filter($matches,function($x){return count($x)>0;}))>=2?"OK":"NG")."<br>";
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21
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+
```
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22
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+
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23
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+
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24
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# 追記
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25
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こっちのほうがまともなアプローチかもしれません
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26
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```PHP
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27
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function check($str){
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28
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$pattern="/([abc])|([ABC])|([123])/";
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29
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preg_match_all($pattern,$str,$matches);
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30
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array_shift($matches);
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31
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return count(array_filter($matches,function($x){
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32
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return count(array_filter($x,function($y){
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33
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return $y!=="";
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34
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}))>0;
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35
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}));
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36
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}
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37
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print check("xyz");
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38
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print check("abcx");
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39
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print check("a3x");
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40
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print check("abc123xyz");
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41
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print check("aB3");
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42
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print check("abcABC123xyz");
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43
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+
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21
44
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```
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