回答編集履歴
2
start追加
test
CHANGED
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@@ -12,7 +12,7 @@
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12
12
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13
13
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let value = input.value; // "2018-W13"
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14
14
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15
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-
return { year: parseInt(value.substring(0, 4), 10), week: parseInt(value.substring(6), 10) };
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15
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+
return { year: parseInt(value.substring(0, 4), 10), week: parseInt(value.substring(6), 10), start: input.valueAsDate };
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16
16
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17
17
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}
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18
18
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@@ -40,6 +40,6 @@
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40
40
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41
41
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var d = new Date(2022, 1, 21);
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42
42
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43
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-
console.log(getWeekInfo(new Date(d - dif))); // {year: 2022, week: 1}
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43
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+
console.log(getWeekInfo(new Date(d - dif))); // {year: 2022, week: 1, start: Mon Jan 03 2022 09:00:00 GMT+0900 (東京 (標準時))}
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44
44
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45
45
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```
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1
解決方法を追記
test
CHANGED
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@@ -2,14 +2,44 @@
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2
2
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3
3
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```JavaScript
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4
4
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5
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-
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5
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+
function getWeekInfo(date) {
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6
6
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7
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-
input
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7
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+
let input = document.createElement('input');
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8
8
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9
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-
input.
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9
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+
input.type = 'week';
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10
10
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11
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+
input.valueAsDate = date;
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12
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+
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11
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-
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13
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+
let value = input.value; // "2018-W13"
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14
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+
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15
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return { year: parseInt(value.substring(0, 4), 10), week: parseInt(value.substring(6), 10) };
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16
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+
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17
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}
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18
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+
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19
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```
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20
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+
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21
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+
-- 17:05 追記
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22
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+
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23
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+
1月4日が含まれる日が1週目ということのようですので、次のようにしてみてはどうでしょうか？
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24
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+
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25
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```JavaScript
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26
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+
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27
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// 差分を出しておく。
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28
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+
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29
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let a = new Date(referenceDate);
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30
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+
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31
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a.setMonth(0);
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32
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+
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33
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a.setDate(4);
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34
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+
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35
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let dif = referenceDate - a;
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12
36
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13
37
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14
38
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39
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+
// 確認したい日付。
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40
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+
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41
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var d = new Date(2022, 1, 21);
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42
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+
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43
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console.log(getWeekInfo(new Date(d - dif))); // {year: 2022, week: 1}
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44
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+
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15
45
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```
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