回答編集履歴
4
テキスト修正
test
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@@ -1,4 +1,8 @@
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1
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-
再帰を使って
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1
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再帰を使ってやってみました。
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5
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（※以下のコードで、メソッド名 `base_of_pascals_triangle` は、「[パスカルの三角形](https://ja.wikipedia.org/wiki/%E3%83%91%E3%82%B9%E3%82%AB%E3%83%AB%E3%81%AE%E4%B8%89%E8%A7%92%E5%BD%A2)の底辺」の意）
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6
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7
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8
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@@ -10,7 +14,7 @@
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10
14
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```ruby
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16
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-
def
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def base_of_pascals_triangle(n)
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18
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if n == 1
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@@ -18,7 +22,7 @@
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else
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prev =
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prev = base_of_pascals_triangle(n-1)
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(0...n).map do |i|
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@@ -32,7 +36,7 @@
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puts "#{
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puts "#{base_of_pascals_triangle(6)}"
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40
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```
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42
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3
テキスト修正
test
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@@ -36,7 +36,7 @@
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36
36
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```
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39
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-
> [ykt68@macbook15]$ ruby te
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> [ykt68@macbook15]$ ruby tera118837.rb
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40
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**[1, 5, 10, 10, 5, 1]**
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2
テキスト修正
test
CHANGED
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@@ -12,21 +12,21 @@
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12
12
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def numbers(n)
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if n == 1
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if n == 1
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[1]
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[1]
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-
else
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else
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-
prev = numbers(n-1)
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prev = numbers(n-1)
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(0...n).map do |i|
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(0...n).map do |i|
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-
(i > 0 ? prev[i-1] : 0) + ( i < prev.length ? prev[i] : 0)
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(i > 0 ? prev[i-1] : 0) + ( i < prev.length ? prev[i] : 0)
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end
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end
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-
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-
end
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end
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32
32
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1
テキスト修正
test
CHANGED
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@@ -20,7 +20,7 @@
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20
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prev = numbers(n-1)
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-
(0...n).
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(0...n).map do |i|
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(i > 0 ? prev[i-1] : 0) + ( i < prev.length ? prev[i] : 0)
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