回答編集履歴
1
sample
test
CHANGED
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@@ -1 +1,47 @@
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1
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基本的には総当たりで処理するしかないでしょう
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3
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4
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# sample
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6
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oracleとちょっと文法が違うかもしれませんが参考までに
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8
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9
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- 元データ
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10
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11
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```SQL
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12
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create table tbl(id int unique,name varchar(10) unique,price int);
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insert into tbl values(1,null,0),(2,'A',10000),(3,'B',10000),(4,'C',10000);
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16
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```
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- 組み合わせ結果
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20
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21
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```
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select
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t1.name as name1
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,t2.name as name2
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,t3.name as name3
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,t1.price+t2.price+t3.price as sum
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32
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from tbl as t1
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left join tbl as t2
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on t1.name!=t2.name and t1.id<t2.id
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or t2.name is null
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left join tbl as t3
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on not t3.name in (t1.name,t2.name) and t1.id<t3.id and t2.id<t3.id
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44
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45
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or t3.name is null
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46
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47
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```
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