回答編集履歴
5
修正後コード対応
answer
CHANGED
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@@ -51,4 +51,72 @@
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51
51
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];
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52
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console.log(make(users, ids));
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53
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// こちらもいい感じの結果に
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54
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+
```
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55
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+
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56
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---
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57
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+
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58
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【追記】 グループ分けしたオブジェクトへの対応版
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59
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60
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条件変わってますので再度考え直してみます。
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61
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まぁ、オブジェクトはtoPairsを使って配列にしてしまえば消化試合です。
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62
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+
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63
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キーに引っかかるグループが存在しなかった場合を考慮して、
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64
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存在しないグループは一度filterで消し飛ばすというガードも組み込みました。
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65
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66
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```JavaScript
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67
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const list = {
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68
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'sports': [
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69
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{identify: 'soccer', name: 'サッカー'},
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70
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{identify: 'baseball', name: '野球'}
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],
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'nature': [
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{identify: 'animal', name: '動物'},
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{identify: 'flower', name: '花'}
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]
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};
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const groups = [
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{identify:'sports', id: 1},
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{identify:'nature', id: 2},
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];
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81
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82
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const make = (tmpList, groups) =>
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83
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_(tmpList)
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84
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.toPairs()
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85
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.filter(([gname]) => _.find(groups, group => group.identify === gname))
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86
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.map(([gname, items]) => {
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const group = _.find(groups, group => group.identify === gname);
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return _.map(items, it => ({...it, group_id: group.id}));
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})
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.flatten()
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.value()
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92
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93
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result = make(list, groups)
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94
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```
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95
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96
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[https://codepen.io/travist/full/jrBjBz/](https://codepen.io/travist/full/jrBjBz/)にコピペすればちゃんと表示されることがわかります。
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97
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結果:
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98
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99
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```JSON
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[
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{
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"identify": "soccer",
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"name": "サッカー",
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"group_id": 1
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},
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{
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"identify": "baseball",
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"name": "野球",
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"group_id": 1
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},
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{
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"identify": "animal",
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"name": "動物",
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"group_id": 2
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},
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{
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"identify": "flower",
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"name": "花",
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"group_id": 2
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}
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]
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54
122
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```
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4
syntaxエラーを修正
answer
CHANGED
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@@ -7,10 +7,22 @@
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7
7
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const make = (tmpList, groups) =>
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8
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_(tmpList)
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.map(tmp =>
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10
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_.map(groups, group => {...tmp, id: group.id})
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10
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_.map(groups, group => ({...tmp, id: group.id}))
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)
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.flatten()
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.values()
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const users = [
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{ user: 'barney', age: 36, active: true },
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{ user: 'fred', age: 40, active: false },
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{ user: 'travis', age: 37, active: true}
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];
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const ids = [
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{ id: 123 },
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{ id: 234 }
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];
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console.log(make(users, ids));
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// いい感じにでました
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14
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```
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---
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@@ -22,9 +34,21 @@
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```JavaScript
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const make = (tmpList, groups) =>
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tmpList
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.map(tmp => groups.map(group => {...tmp, id: group.id}))
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.map(tmp => groups.map(group => ({...tmp, id: group.id})))
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.reduce((arr, items) => {
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items.forEach(it => { arr.push(it) });
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return arr;
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}, [])
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+
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const users = [
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{ user: 'barney', age: 36, active: true },
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{ user: 'fred', age: 40, active: false },
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{ user: 'travis', age: 37, active: true}
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];
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48
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const ids = [
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49
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{ id: 123 },
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50
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{ id: 234 }
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51
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];
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52
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console.log(make(users, ids));
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53
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+
// こちらもいい感じの結果に
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30
54
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```
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3
tmp使ってなかった
answer
CHANGED
|
@@ -7,7 +7,7 @@
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7
7
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const make = (tmpList, groups) =>
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8
8
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_(tmpList)
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9
9
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.map(tmp =>
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10
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-
_.map(groups, group => {...
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10
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+
_.map(groups, group => {...tmp, id: group.id})
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)
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.flatten()
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13
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.values()
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@@ -22,7 +22,7 @@
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22
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```JavaScript
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const make = (tmpList, groups) =>
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tmpList
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-
.map(tmp => groups.map(group => {...
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.map(tmp => groups.map(group => {...tmp, id: group.id}))
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.reduce((arr, items) => {
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items.forEach(it => { arr.push(it) });
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return arr;
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2
reduce使うルート間違ってるやん
answer
CHANGED
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@@ -23,5 +23,8 @@
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23
23
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const make = (tmpList, groups) =>
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tmpList
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.map(tmp => groups.map(group => {...tmpList, id: group.id}))
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.reduce((arr, items) => {
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26
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-
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items.forEach(it => { arr.push(it) });
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return arr;
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}, [])
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```
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1
おまけ追加
answer
CHANGED
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@@ -11,4 +11,17 @@
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11
11
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)
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12
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.flatten()
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.values()
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14
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```
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15
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16
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---
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17
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18
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【おまけ】
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19
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20
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+
reduce使うルートならネイティブJSでも出来そうなのでやりました。
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21
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+
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22
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+
```JavaScript
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23
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const make = (tmpList, groups) =>
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24
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tmpList
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25
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.map(tmp => groups.map(group => {...tmpList, id: group.id}))
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.reduce((arr, it) => { arr.push(it); return arr; }, [])
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14
27
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```
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