回答編集履歴
3
推敲
test
CHANGED
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@@ -1,3 +1,7 @@
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1
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提示のSQLだと単に```ORDER BY '文字列'```にしかなりませんから、ソートは掛かりませんね。
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2
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3
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5
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以下ではどうですか。
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2
6
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3
7
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```SQL
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2
推敲
test
CHANGED
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@@ -12,7 +12,7 @@
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12
12
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ORDER BY B.SUB_KEY desc
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15
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-
, case when sortKbn!=20 then A.SUB_KEY end desc
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, case when sortKbn!='20' then A.SUB_KEY end desc
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16
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```
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18
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@@ -32,10 +32,10 @@
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WHERE A.KEY = B.KEY
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-
ORDER BY case when sortKbn=20 then B.SUB_KEY end desc
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ORDER BY case when sortKbn='20' then B.SUB_KEY end desc
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-
, case when sortKbn!=20 then B.SUB_KEY end
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, case when sortKbn!='20' then B.SUB_KEY end
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-
, case when sortKbn!=20 then A.SUB_KEY end desc
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, case when sortKbn!='20' then A.SUB_KEY end desc
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40
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```
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1
追記
test
CHANGED
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@@ -15,3 +15,27 @@
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15
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, case when sortKbn!=20 then A.SUB_KEY end desc
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16
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```
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19
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追記
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20
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21
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---
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22
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23
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条件によって、B.SUB_KEYの昇順/降順が切り替わるのを見落としていました。
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```SQL
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CURSOR C_CUSTOMER(sortKbn IN NVARCHAR2) IS
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SELECT A.*
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FROM A, B
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32
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WHERE A.KEY = B.KEY
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34
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35
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ORDER BY case when sortKbn=20 then B.SUB_KEY end desc
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36
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37
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, case when sortKbn!=20 then B.SUB_KEY end
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38
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39
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, case when sortKbn!=20 then A.SUB_KEY end desc
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40
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41
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```
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