回答編集履歴
3
推敲
answer
CHANGED
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@@ -1,3 +1,5 @@
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1
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+
提示のSQLだと単に```ORDER BY '文字列'```にしかなりませんから、ソートは掛かりませんね。
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2
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+
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1
3
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以下ではどうですか。
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2
4
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```SQL
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3
5
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CURSOR C_CUSTOMER(sortKbn IN NVARCHAR2) IS
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2
推敲
answer
CHANGED
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@@ -5,7 +5,7 @@
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5
5
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FROM A, B
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6
6
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WHERE A.KEY = B.KEY
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7
7
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ORDER BY B.SUB_KEY desc
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8
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-
, case when sortKbn!=20 then A.SUB_KEY end desc
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8
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+
, case when sortKbn!='20' then A.SUB_KEY end desc
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9
9
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```
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10
10
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追記
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11
11
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---
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@@ -15,7 +15,7 @@
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15
15
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SELECT A.*
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16
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FROM A, B
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17
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WHERE A.KEY = B.KEY
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18
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-
ORDER BY case when sortKbn=20 then B.SUB_KEY end desc
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18
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+
ORDER BY case when sortKbn='20' then B.SUB_KEY end desc
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19
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-
, case when sortKbn!=20 then B.SUB_KEY end
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19
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+
, case when sortKbn!='20' then B.SUB_KEY end
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20
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-
, case when sortKbn!=20 then A.SUB_KEY end desc
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20
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+
, case when sortKbn!='20' then A.SUB_KEY end desc
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21
21
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```
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1
追記
answer
CHANGED
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@@ -6,4 +6,16 @@
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6
6
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WHERE A.KEY = B.KEY
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7
7
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ORDER BY B.SUB_KEY desc
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8
8
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, case when sortKbn!=20 then A.SUB_KEY end desc
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9
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+
```
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10
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+
追記
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11
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+
---
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12
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+
条件によって、B.SUB_KEYの昇順/降順が切り替わるのを見落としていました。
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13
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```SQL
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14
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CURSOR C_CUSTOMER(sortKbn IN NVARCHAR2) IS
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15
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SELECT A.*
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16
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FROM A, B
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17
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WHERE A.KEY = B.KEY
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18
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ORDER BY case when sortKbn=20 then B.SUB_KEY end desc
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19
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+
, case when sortKbn!=20 then B.SUB_KEY end
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20
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+
, case when sortKbn!=20 then A.SUB_KEY end desc
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9
21
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```
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