回答編集履歴
1
edit
answer
CHANGED
|
@@ -1,2 +1,29 @@
|
|
|
1
1
|
変数のスコープについて知る必要があります。
|
|
2
|
-
https://qiita.com/yoichi22/items/8ae2ca180407a5ad5a6d
|
|
2
|
+
https://qiita.com/yoichi22/items/8ae2ca180407a5ad5a6d
|
|
3
|
+
|
|
4
|
+
---
|
|
5
|
+
|
|
6
|
+
解決法はいくつかありますが、このままの雰囲気を保ったものを2つだけ。
|
|
7
|
+
|
|
8
|
+
パターン1：`keys.py`
|
|
9
|
+
```python
|
|
10
|
+
api_key = 'API1'
|
|
11
|
+
if api_key == 'API1':
|
|
12
|
+
name = ...
|
|
13
|
+
CONSUMER_KEY = ...
|
|
14
|
+
elif api_key == 'API2':
|
|
15
|
+
name = ...
|
|
16
|
+
```
|
|
17
|
+
|
|
18
|
+
パターン2：`keys.py`
|
|
19
|
+
```python
|
|
20
|
+
def API1():
|
|
21
|
+
name = ...
|
|
22
|
+
CONSUMER_KEY = ...
|
|
23
|
+
...
|
|
24
|
+
return name, CONSUMER_KEY, .....
|
|
25
|
+
def API2():
|
|
26
|
+
...
|
|
27
|
+
|
|
28
|
+
name, CONSUMER_KEY, ... = API1()
|
|
29
|
+
```
|