回答編集履歴
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追記
test
CHANGED
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@@ -29,3 +29,35 @@
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29
29
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select bean,sum(num)/(select sum(num) from tbl) as ratio from tbl group by bean
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30
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```
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32
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+
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33
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# 追記
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34
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35
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> １レコード１件とした場合でもsumでさまれるのでしょうか？
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36
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+
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37
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38
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39
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こういうことですか？
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40
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41
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```SQL
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42
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43
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create table tbl2(bean varchar(10),num int);
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44
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45
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insert into tbl2 values
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46
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('cacao ',9),
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48
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('coffe ',4),
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('sanbia ',1);
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select bean,num,num/(select sum(num) from tbl2) as ratio from tbl2
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54
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```
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56
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57
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sanbiaのデータだけ
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```SQL
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select num/(select sum(num) from tbl2) as ratio from tbl2 where bean='sanbia'
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62
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```
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