回答編集履歴
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追記
answer
CHANGED
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@@ -13,4 +13,20 @@
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13
13
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('sanbia','g',1);
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15
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select bean,sum(num)/(select sum(num) from tbl) as ratio from tbl group by bean
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16
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```
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17
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# 追記
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18
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> １レコード１件とした場合でもsumでさまれるのでしょうか？
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19
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+
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20
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こういうことですか？
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21
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```SQL
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22
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create table tbl2(bean varchar(10),num int);
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insert into tbl2 values
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('cacao ',9),
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25
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('coffe ',4),
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('sanbia ',1);
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select bean,num,num/(select sum(num) from tbl2) as ratio from tbl2
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28
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```
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29
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sanbiaのデータだけ
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30
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```SQL
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31
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select num/(select sum(num) from tbl2) as ratio from tbl2 where bean='sanbia'
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16
32
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```
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