回答編集履歴
2
追記
answer
CHANGED
@@ -27,4 +27,27 @@
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27
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$stmt->fetchAll();
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*/
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?>
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30
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```
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# あいまい検索
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- その1
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33
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```PHP
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34
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if($keyword!=="" and is_array($keywords) and count($keywords)>0){
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$sql.="AND (0 ";
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36
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foreach(["id","name"] as $v1){
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$sql.=str_repeat("OR $v1 LIKE CONCAT('%',?,'%') ",count($keywords));
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$data=array_merge($data,$keywords);
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}
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$sql.=") ";
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}
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```
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- その2
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44
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```PHP
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45
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if($keyword!=="" and is_array($keywords) and count($keywords)>0){
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$sql.="AND (0 ";
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foreach(["id","name"] as $v1){
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$sql.="OR $v1 REGEXP CONCAT(".implode(",'|',",array_fill(0,count($keywords),"?")).") ";
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$data=array_merge($data,$keywords);
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}
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$sql.=") ";
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}
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53
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```
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1
調整
answer
CHANGED
@@ -11,7 +11,7 @@
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11
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var_dump($keywords);
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$data=[];
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$sql = "SELECT * FROM table WHERE 1 ";
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-
if(is_array($keywords) and count($keywords)>0){
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14
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+
if($keyword!=="" and is_array($keywords) and count($keywords)>0){
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$sql.="AND (0 ";
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foreach(["id","name"] as $v1){
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$sql.="OR $v1 IN(".implode(",",array_fill(0,count($keywords),"?")).") ";
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