回答編集履歴
2
修正
test
CHANGED
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@@ -24,19 +24,11 @@
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24
24
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25
25
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inner join (
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26
26
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27
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-
select sub_id, sum(qty) as sum_qty from test group by sub_id
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27
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+
select sub_id, max(up_time) as max_up_time, sum(qty) as sum_qty from test group by sub_id
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28
28
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29
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) as t2
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30
30
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31
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-
on t1.sub_id=t2.sub_id
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31
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+
on t1.sub_id=t2.sub_id and t1.up_time=t2.max_up_time
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32
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-
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33
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-
inner join (
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34
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-
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35
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-
select sub_id, max(up_time) as sum_qty from test group by sub_id
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36
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-
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37
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-
) as t2
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38
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-
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39
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-
on t1.sub_id=t3.sub_id
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40
32
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41
33
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```
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42
34
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1
追記
test
CHANGED
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@@ -13,3 +13,33 @@
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13
13
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where up_time=(select max(up_time) from test where sub_id=t1.sub_id)
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14
14
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15
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```
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16
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+
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17
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+
一応別解（相関問い合わせによるサブクエリーを使用しない版）
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18
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+
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19
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+
```SQL
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20
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+
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21
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+
select t1.up_time, t1.picupno, t2.sum_qty
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22
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+
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23
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from test as t1
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24
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+
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25
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+
inner join (
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26
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+
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27
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+
select sub_id, sum(qty) as sum_qty from test group by sub_id
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28
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+
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29
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+
) as t2
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30
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+
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31
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+
on t1.sub_id=t2.sub_id
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32
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+
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33
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+
inner join (
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34
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+
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35
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+
select sub_id, max(up_time) as sum_qty from test group by sub_id
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36
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+
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37
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+
) as t2
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38
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+
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39
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+
on t1.sub_id=t3.sub_id
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40
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+
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41
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+
```
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42
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+
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43
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+
MySQLはサンプルデータを触っている程度なので、大量のデータでのSQLの記述による性能差などは見地がありません。
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44
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+
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45
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+
なので、結果をフィードバックして頂けると喜びます。
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