回答編集履歴
1
追記
answer
CHANGED
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@@ -12,6 +12,8 @@
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12
12
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array_push($data,$val,$a["active_flag"][$key],$a["user_name"][$key]);
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13
13
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}
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14
14
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$sql.=implode(",",array_fill(0,count($a["id"]),"(?,?,?)"));
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15
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+
/*以下1行追記、カラム名は環境にあわせてください*/
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16
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+
$sql.=" on duplicate key update active_flag=values(active_flag),user_name=values(user_name)";
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15
17
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print_r($data);
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16
18
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print $sql;
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17
19
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```
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