回答編集履歴
1
追記
test
CHANGED
|
@@ -5,3 +5,31 @@
|
|
|
5
5
|
同じCOUNT数の場合同順とし、その後のデータが後ろたおしすればいいのでしょうか？
|
|
6
6
|
|
|
7
7
|
例示のものでいうとcount=3が1位、count=2が2位、count=1が4位？
|
|
8
|
+
|
|
9
|
+
|
|
10
|
+
|
|
11
|
+
# 追記
|
|
12
|
+
|
|
13
|
+
|
|
14
|
+
|
|
15
|
+
集計後のデータを最終形すると処理自体は冗長になります
|
|
16
|
+
|
|
17
|
+
とりあえずこうしてみてください
|
|
18
|
+
|
|
19
|
+
|
|
20
|
+
|
|
21
|
+
```SQL
|
|
22
|
+
|
|
23
|
+
select good,count,
|
|
24
|
+
|
|
25
|
+
(select count(*)+1 from
|
|
26
|
+
|
|
27
|
+
(select good,count(*) as count from vote group by good) as t2
|
|
28
|
+
|
|
29
|
+
where t1.count<t2.count) as rank
|
|
30
|
+
|
|
31
|
+
from (select good,count(*) as count from vote group by good) as t1
|
|
32
|
+
|
|
33
|
+
order by rank asc,good asc
|
|
34
|
+
|
|
35
|
+
```
|