回答編集履歴
2
誤記修正
answer
CHANGED
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@@ -16,5 +16,5 @@
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16
16
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Line = $_.Line -replace $pattern, ""
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17
17
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Filename = $_.Filename
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18
18
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}
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19
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-
} | select Line, Filename
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19
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+
} | select Line, Filename
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20
20
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```
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1
誤記修正
answer
CHANGED
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@@ -4,7 +4,7 @@
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4
4
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5
5
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```powershell
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6
6
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Select-String $pattern $path -Encoding default |
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7
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-
select @{Label="Line"
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7
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+
select @{Label="Line"; Expression={$_.Line -replace $pattern, ""}}, Filename
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8
8
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```
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9
9
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10
10
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- ForEachで新規オブジェクトを作成する
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