回答編集履歴
17
消去
test
CHANGED
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-
CakePHP3
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CakePHP3での例はdangaoさんの回答を参照してください。
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```php
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$table = TableRegistry::get('Jobs');
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$q = $table->find();
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$q
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->select($table)
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->leftJoinWith('Assigns')
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->group('Jobs.id')
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->having([
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$q->func()->count('Assigns.user_id')->lt(3),
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$q->func()->coalesce([
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$q->func()->sum($q->newExpr('Assigns.user_id')->notEq(2)),
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0,
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])->eq(0)
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]);
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```
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↑ノリで書いてみました,動くかどうかは知りません
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以降
test
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CakePHP3.1
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CakePHP3.1以降での例
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3\.1
test
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CakePHP3 での例
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CakePHP3.1 での例
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14
SELECT
test
CHANGED
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```php
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$
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$table = TableRegistry::get('Jobs');
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$q = $table->find();
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$q
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->select($
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->select($table)
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->leftJoinWith('Assigns')
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13
内側に変数があるのでやっぱり消す
test
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↑ノリで書いてみました,動くかどうかは知りません
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```php
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$q = TableRegistry::get('Jobs')->find();
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$q
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->select($q)
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->leftJoinWith('Assigns')
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->group('Jobs.id')
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->having([
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'COUNT(Assigns.user_id) <' => 3,
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'COALESCE(SUM(Assigns.user_id != 2), 0)' => 0,
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]);
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```
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↑これぐらいでも十分かもしれませんね,ORMによる行き過ぎた抽象化はアンチパターンです
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12
func\(\)使わない方法
test
CHANGED
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↑ノリで書いてみました,動くかどうかは知りません
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```php
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$q = TableRegistry::get('Jobs')->find();
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$q
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->select($q)
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->leftJoinWith('Assigns')
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->group('Jobs.id')
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->having([
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'COUNT(Assigns.user_id) <' => 3,
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'COALESCE(SUM(Assigns.user_id != 2), 0)' => 0,
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]);
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```
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↑これぐらいでも十分かもしれませんね,ORMによる行き過ぎた抽象化はアンチパターンです
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11
coalesce args
test
CHANGED
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$q->func()->count('Assigns.user_id')->lt(3),
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$q->func()->coalesce(
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$q->func()->coalesce([
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$q->newExpr('Assigns.user_id')->notEq(2)
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$q->func()->sum($q->newExpr('Assigns.user_id')->notEq(2)),
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0,
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)
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])->eq(0)
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]);
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10
Group
test
CHANGED
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->leftJoinWith('Assigns')
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->group('
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->group('Jobs.id')
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->having([
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9
CakePHP3
test
CHANGED
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```php
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$q = TableRegistry::get('Jobs');
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$q = TableRegistry::get('Jobs')->find();
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$q
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->select($q)
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->leftJoinWith('Assigns')
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@@ -158,7 +160,11 @@
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$q->func()->count('Assigns.user_id')->lt(3),
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$q->func()->coalesce($q->func()->sum(
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$q->
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$q->newExpr('Assigns.user_id')->notEq(2)
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), 0)->eq(0)
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]);
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8
CakePHP3
test
CHANGED
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HAVING句のみだとフルインデックススキャンになってしまうので,総数が多い場合はジョブを絞り込むためのWHERE句が適宜必要です。
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HAVING句のみだとフルインデックススキャンになってしまうので,総数が多い場合はジョブを絞り込むためのWHERE句が適宜必要です。
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@@ -139,3 +139,31 @@
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- `COALESCE(SUM(assigns.user_id = 2), 0)` でユーザ2にアサインされている数を取得できる。論理式の結果は1または0になり,これが集計される。但し誰に対するアサインも存在しない場合はNULLになってしまうので,その場合は数値の0に変換している。
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CakePHP3 での例
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```php
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$q = TableRegistry::get('Jobs');
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$q->find()
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->leftJoinWith('Assigns')
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->group('Assigns.job_id')
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->having([
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$q->func()->count('Assigns.user_id')->lt(3),
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$q->func()->coalesce($q->func()->sum($q->newExpr('Assigns.user_id')->notEq(2)), 0)->eq(0)
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]);
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```
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↑ノリで書いてみました,動くかどうかは知りません
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7
補足
test
CHANGED
@@ -127,3 +127,15 @@
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HAVING句のみだとフルインデックススキャンになってしまうので,総数が多い場合はジョブを絞り込むためのWHERE句が適宜必要です。また,CakePHP3はちょっとまだ使ったことがほとんど無いので,ORMを使った回答は他の人に任せます。
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【ポイント】
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- `COUNT(assigns.user_id)` でアサインされている数を取得できる。COUNTの引数にLEFT JOINのターゲットのカラムを指定しているので,存在しない場合は0になる。
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- `COALESCE(SUM(assigns.user_id = 2), 0)` でユーザ2にアサインされている数を取得できる。論理式の結果は1または0になり,これが集計される。但し誰に対するアサインも存在しない場合はNULLになってしまうので,その場合は数値の0に変換している。
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6
大幅に修正
test
CHANGED
@@ -56,17 +56,13 @@
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```sql
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SELECT jobs.
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SELECT jobs.* FROM jobs
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LEFT JOIN assigns ON assigns.job_id = jobs.id
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GROUP BY jobs.id
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GROUP BY jobs.id
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HAVING COUNT(assigns.user_id) < 3 AND COALESCE(SUM(assigns.user_id = 2), 0) = 0;
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) jobs;
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```
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```
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mysql> SELECT jobs.
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mysql> SELECT jobs.* FROM jobs
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->
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-> LEFT JOIN assigns ON assigns.job_id = jobs.id
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->
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-> GROUP BY jobs.id
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-> GROUP BY jobs.id
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->
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-> HAVING COUNT(assigns.user_id) < 3 AND COALESCE(SUM(assigns.user_id = 2), 0) = 0;
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-> ) jobs;
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+----+------+
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mysql> EXPLAIN
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-> SELECT jobs.
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-> SELECT jobs.* FROM jobs
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->
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-> LEFT JOIN assigns ON assigns.job_id = jobs.id
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->
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-> GROUP BY jobs.id
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->
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-> HAVING COUNT(assigns.user_id) < 3 AND COALESCE(SUM(assigns.user_id = 2), 0) = 0;
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+----+-------------+---------+-------+---------------+---------+---------+-----------------+------+-------------+
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-
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| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
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+----+-------------+---------
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+----+-------------+---------+-------+---------------+---------+---------+-----------------+------+-------------+
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| 1 | SIMPLE | jobs | index | PRIMARY | PRIMARY | 4 | NULL | 4 | NULL |
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| 1 | SIMPLE | assigns | ref | job_id | job_id | 4 | example.jobs.id | 1 | Using index |
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+----+-------------+---------+-------+---------------+---------+---------+-----------------+------+-------------+
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| 2 | DERIVED | jobs | index | PRIMARY | PRIMARY | 4 | NULL | 4 | NULL |
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2 rows in set (0.00 sec)
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+----+-------------+------------+-------+---------------+---------+---------+-----------------+------+-------------+
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```
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5
補足
test
CHANGED
@@ -140,4 +140,4 @@
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-
CakePHP3はちょっとまだ使ったことがほとんど無いので他の人に
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+
HAVING句のみだとフルインデックススキャンになってしまうので,総数が多い場合はジョブを絞り込むためのWHERE句が適宜必要です。また,CakePHP3はちょっとまだ使ったことがほとんど無いので,ORMを使った回答は他の人に任せます。
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4
assignee
test
CHANGED
@@ -58,13 +58,13 @@
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SELECT jobs.id, jobs.name FROM (
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SELECT jobs.*, assigns.user_id AS assigne
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SELECT jobs.*, assigns.user_id AS assignee_id FROM jobs
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LEFT JOIN assigns ON assigns.job_id = jobs.id
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GROUP BY jobs.id
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HAVING (SUM(1) < 3 AND assigne
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HAVING (SUM(1) < 3 AND assignee_id != 2) OR assignee_id IS NULL
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) jobs;
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mysql> SELECT jobs.id, jobs.name FROM (
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-> SELECT jobs.*, assigns.user_id AS assigne
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-> SELECT jobs.*, assigns.user_id AS assignee_id FROM jobs
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-> LEFT JOIN assigns ON assigns.job_id = jobs.id
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-> GROUP BY jobs.id
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-> HAVING (SUM(1) < 3 AND assigne
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-> HAVING (SUM(1) < 3 AND assignee_id != 2) OR assignee_id IS NULL
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-> ) jobs;
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-> SELECT jobs.id, jobs.name FROM (
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-> SELECT jobs.*, assigns.user_id AS assigne
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-> SELECT jobs.*, assigns.user_id AS assignee_id FROM jobs
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-> LEFT JOIN assigns ON assigns.job_id = jobs.id
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-> GROUP BY jobs.id
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-> HAVING (SUM(1) < 3 AND assigne
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-> HAVING (SUM(1) < 3 AND assignee_id != 2) OR assignee_id IS NULL
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-> ) jobs;
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3
補足
test
CHANGED
@@ -1,4 +1,4 @@
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-
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+
テーブル生成
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2
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3
3
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4
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@@ -137,3 +137,7 @@
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+----+-------------+------------+-------+---------------+---------+---------+-----------------+------+-------------+
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```
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+
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+
|
143
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+
CakePHP3はちょっとまだ使ったことがほとんど無いので他の人に回答任せます
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2
補足
test
CHANGED
@@ -69,3 +69,71 @@
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) jobs;
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```
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結果と実行計画の確認
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```
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+
mysql> SELECT jobs.id, jobs.name FROM (
|
82
|
+
|
83
|
+
-> SELECT jobs.*, assigns.user_id AS assigned_user_id FROM jobs
|
84
|
+
|
85
|
+
-> LEFT JOIN assigns ON assigns.job_id = jobs.id
|
86
|
+
|
87
|
+
-> GROUP BY jobs.id
|
88
|
+
|
89
|
+
-> HAVING (SUM(1) < 3 AND assigned_user_id != 2) OR assigned_user_id IS NULL
|
90
|
+
|
91
|
+
-> ) jobs;
|
92
|
+
|
93
|
+
+----+------+
|
94
|
+
|
95
|
+
| id | name |
|
96
|
+
|
97
|
+
+----+------+
|
98
|
+
|
99
|
+
| 2 | Job2 |
|
100
|
+
|
101
|
+
| 4 | Job4 |
|
102
|
+
|
103
|
+
+----+------+
|
104
|
+
|
105
|
+
2 rows in set (0.00 sec)
|
106
|
+
|
107
|
+
|
108
|
+
|
109
|
+
|
110
|
+
|
111
|
+
mysql> EXPLAIN
|
112
|
+
|
113
|
+
-> SELECT jobs.id, jobs.name FROM (
|
114
|
+
|
115
|
+
-> SELECT jobs.*, assigns.user_id AS assigned_user_id FROM jobs
|
116
|
+
|
117
|
+
-> LEFT JOIN assigns ON assigns.job_id = jobs.id
|
118
|
+
|
119
|
+
-> GROUP BY jobs.id
|
120
|
+
|
121
|
+
-> HAVING (SUM(1) < 3 AND assigned_user_id != 2) OR assigned_user_id IS NULL
|
122
|
+
|
123
|
+
-> ) jobs;
|
124
|
+
|
125
|
+
+----+-------------+------------+-------+---------------+---------+---------+-----------------+------+-------------+
|
126
|
+
|
127
|
+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
|
128
|
+
|
129
|
+
+----+-------------+------------+-------+---------------+---------+---------+-----------------+------+-------------+
|
130
|
+
|
131
|
+
| 1 | PRIMARY | <derived2> | ALL | NULL | NULL | NULL | NULL | 4 | NULL |
|
132
|
+
|
133
|
+
| 2 | DERIVED | jobs | index | PRIMARY | PRIMARY | 4 | NULL | 4 | NULL |
|
134
|
+
|
135
|
+
| 2 | DERIVED | assigns | ref | job_id | job_id | 4 | example.jobs.id | 1 | Using index |
|
136
|
+
|
137
|
+
+----+-------------+------------+-------+---------------+---------+---------+-----------------+------+-------------+
|
138
|
+
|
139
|
+
```
|
1
補足
test
CHANGED
@@ -50,6 +50,10 @@
|
|
50
50
|
|
51
51
|
|
52
52
|
|
53
|
+
アサイン数3未満でユーザ2に対するアサインがまだ付いていないジョブを選択
|
54
|
+
|
55
|
+
|
56
|
+
|
53
57
|
```sql
|
54
58
|
|
55
59
|
SELECT jobs.id, jobs.name FROM (
|
@@ -60,7 +64,7 @@
|
|
60
64
|
|
61
65
|
GROUP BY jobs.id
|
62
66
|
|
63
|
-
HAVING (SUM(1) < 3 AND
|
67
|
+
HAVING (SUM(1) < 3 AND assigned_user_id != 2) OR assigned_user_id IS NULL
|
64
68
|
|
65
69
|
) jobs;
|
66
70
|
|