回答編集履歴
5
最終型
test
CHANGED
@@ -108,8 +108,62 @@
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# 入れ子集合モデルのsample(プロシージャをPHPに置き換え版)
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SQLのプロシージャがどうしても作れないのであれば、以下PHPで代替できます
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```PHP
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$pdo->beginTransaction();
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$sql ="UPDATE tbl SET level=0,l=0,r=0;\n";
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$stmt= $pdo->query($sql);
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$sql ="UPDATE tbl SET level=1,l=(SELECT @a:=@a+1 FROM (SELECT @a:=0) AS sub),r=@a:=@a+1 WHERE parent_id IS NULL ORDER BY id;";
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$stmt= $pdo->query($sql);
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$sql ="SELECT id FROM tbl WHERE level=0 ORDER BY parent_id ASC,id DESC;";
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$stmt2 = $pdo->query($sql);
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while($row=$stmt2->fetch()){
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$sql ='UPDATE tbl as a1,tbl as a2,tbl as a3 SET a1.l=a2.l+1,a1.r=a2.l+2,a1.level=a2.level+1,a2.r=a2.r+2,a3.r=a3.r+2 WHERE a1.parent_id=a2.id AND a2.l<a3.r AND a1.id=?;';
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$stmt = $pdo->prepare($sql);
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$stmt->execute([$row["id"]]);
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$sql ='UPDATE tbl as a1,tbl as a2,tbl as a3 SET a3.l=a3.l+2 WHERE a1.parent_id=a2.id AND a2.l<a3.l and a3.id!=a1.id AND a1.id=?;';
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$stmt = $pdo->prepare($sql);
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$stmt->execute([$row["id"]]);
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}
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$sql ='SELECT name,level,(SELECT COUNT(*)-1 FROM tbl AS t2 WHERE t2.l BETWEEN t1.l AND t1.r) AS child FROM tbl AS t1 ORDER BY l;';
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$stmt = $pdo->query($sql);
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$rows=$stmt->fetchAll();
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$pdo->commit();// 実はロールバックしてもOK $pdo->rollback();
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```
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# 入れ子集合モデルのsample
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隣接モデルを入れ子集合モデルに変換するために
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以下のプロシージャを作っておきます。
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4
ついで
test
CHANGED
@@ -331,3 +331,23 @@
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```
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ついでなので子要素の数を調べるにはこうです
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```SQL
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SELECT name,level,(SELECT COUNT(*)-1 FROM tbl AS t2 WHERE t2.l BETWEEN t1.l AND t1.r) AS child FROM tbl AS t1 ORDER BY l
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```
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これを上記PHPの「print $row["name"];」の下の行に以下を追記するだけです
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```PHP
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if($row["child"]>0) print "(".$row["child"].")";
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```
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3
修正
test
CHANGED
@@ -36,7 +36,7 @@
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l int not null,
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int not null);
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r int not null); /*修正*/
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@@ -74,6 +74,40 @@
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id|parent_id|name|sort|level|l|r
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|--:|--:|:--|--:|--:|--:|--:|
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1|NULL|0|1|0|0|0
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2|NULL|1|2|0|0|0
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3|2|1-1|3|0|0|0
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4|2|1-2|4|0|0|0
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5|2|1-3|5|0|0|0
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6|NULL|2|6|0|0|0
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7|NULL|3|7|0|0|0
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8|7|3-1|8|0|0|0
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9|7|3-2|9|0|0|0
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10|9|3-2-1|10|0|0|0
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11|9|3-2-2|11|0|0|0
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12|9|3-2-3|12|0|0|0
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13|7|3-3|13|0|0|0
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14|NULL|4|14|0|0|0
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# 入れ子集合モデルのsample
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隣接モデルを入れ子集合モデルに変換するために
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@@ -172,24 +206,128 @@
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```
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※プロシージャ実行後
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id|parent_id|name|sort|level|l|r
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|--:|--:|--:|--:|--:|--:|--:|
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1|NULL|0|1|1|1|2
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2|NULL|1|2|1|3|10
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3|2|1-1|3|2|4|5
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4|2|1-2|4|2|6|7
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5|2|1-3|5|2|8|9
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6|NULL|2|6|1|11|12
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7|NULL|3|7|1|13|26
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8|7|3-1|8|2|14|15
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9|7|3-2|9|2|16|23
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10|9|3-2-1|10|3|17|18
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11|9|3-2-2|11|3|19|20
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12|9|3-2-3|12|3|21|22
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13|7|3-3|13|2|24|25
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14|NULL|4|14|1|27|28
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nameを階層で表示し、含まれる子要素数を表示
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COUNT1は直接の子要素数のみ、COUNT2は孫以降の要素数も含む
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```SQL
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SELECT CONCAT( REPEAT( "__", t1.level -1 ) , t1.name ) AS name
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-
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,(SELECT count(*)-1 from tbl as t3 WHERE t3.l BETWEEN t1.l AND t1.r and t3.level<=t1.level+1) AS COUNT1
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-
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,(SELECT count(*)-1 from tbl as t2 WHERE t2.l BETWEEN t1.l AND t1.r) AS COUNT1
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FROM tbl
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SELECT * FROM tbl ORDER BY l
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-
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-
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-
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```
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```
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-
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phpでデータをあつめて
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-
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$rows=$stmt->fetchAll(PDO::FETCH_ASSOC);
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としたとき
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```PHP
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$indent=3;
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$l1=0;
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foreach($rows as $key=>$row){
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$l2=$row["level"];
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$l3=($key<count($rows)-1)?$rows[$key+1]["level"]:0;
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if($l1>=$l2){
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print str_repeat(" ",($l2-1)*$indent);
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}
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if($l1<$l2){
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print PHP_EOL;
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print str_repeat(" ",($l2-1)*$indent);
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print "<ul>".PHP_EOL;
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print str_repeat(" ",($l2-1)*$indent);
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}
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print "<li>";
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print $row["name"];
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if($l2==$l3){
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print "</li>".PHP_EOL;;
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}
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if($l2>$l3){
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print "</li>".PHP_EOL;
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for($i=$l2-$l3-1;$i>0;$i--){
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print str_repeat(" ",($i)*$indent);
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print "</ul>".PHP_EOL;
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print str_repeat(" ",($i-1)*$indent);
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print "</li>".PHP_EOL;
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}
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print str_repeat(" ",($l3)*$indent);
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print "</ul>".PHP_EOL;
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}
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$l1=$l2;
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}
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```
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2
sample
test
CHANGED
@@ -11,3 +11,185 @@
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11
11
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基本的にご提示されている「経路列挙モデル」より「隣接モデル」で
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13
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データをもち「入れ子集合モデル」に変換して利用するほうがラクです
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# 隣接モデルのsample
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隣接モデルでは、親のidだけ保存します。
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21
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親がいない=NULLが先頭になります
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22
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23
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(入れ子集合モデル用にlevelと、l(左)、r(右)を用意してあります)
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24
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```SQL
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26
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27
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CREATE TABLE tbl(id INT NOT NULL UNIQUE,
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29
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parent_id INT NULL,
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31
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name varchar(64),
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32
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33
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sort int,
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34
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35
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level int NOT NULL,
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36
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+
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37
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l int not null,
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38
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int not null);
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INSERT INTO tbl(id,parent_id, name,sort) VALUES
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44
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(1,null,'0',1),
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(2,null,'1',2),
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+
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49
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(3,2,'1-1',3),
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51
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(4,2,'1-2',4),
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52
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53
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(5,2,'1-3',5),
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(6,null,'2',6),
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(7,null,'3',7),
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(8,7,'3-1',8),
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(9,7,'3-2',9),
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(10,9,'3-2-1',10),
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+
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65
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(11,9,'3-2-2',11),
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67
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(12,9,'3-2-3',12),
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+
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(13,7,'3-3',13),
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71
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(14,null,'4',14);
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+
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73
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```
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74
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|
75
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+
|
76
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+
|
77
|
+
# 入れ子集合モデルのsample
|
78
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+
|
79
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+
隣接モデルを入れ子集合モデルに変換するために
|
80
|
+
|
81
|
+
以下のプロシージャを作っておきます。
|
82
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+
|
83
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+
```SQL
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84
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|
85
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DROP PROCEDURE IF EXISTS SET_LR;
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86
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|
87
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DELIMITER //
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88
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+
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CREATE PROCEDURE SET_LR()
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90
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+
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91
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BEGIN
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+
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93
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DECLARE a INT DEFAULT 0;
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94
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+
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95
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DECLARE done INT DEFAULT 0;
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96
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+
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97
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DECLARE CUR CURSOR FOR
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98
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+
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99
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SELECT id FROM tbl WHERE level=0 ORDER BY parent_id ASC,sort DESC,id DESC;
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100
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+
|
101
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DECLARE CONTINUE HANDLER FOR SQLSTATE '02000' SET done = 1;
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102
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+
|
103
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UPDATE tbl SET level=0,l=0,r=0;
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104
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+
|
105
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/* level,l,rを初期化*/
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106
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+
|
107
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+
|
108
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+
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109
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UPDATE tbl SET level=1,l=(SELECT @a:=@a+1 FROM (SELECT @a:=0) AS sub),r=@a:=@a+1
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110
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+
|
111
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WHERE parent_id IS NULL
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112
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+
|
113
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ORDER BY sort ASC,id ASC;
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114
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+
|
115
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/* 先頭データのlevelを1とし、l,rを1ずつ足していく*/
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116
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+
|
117
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+
|
118
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+
|
119
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+
OPEN CUR;
|
120
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+
|
121
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+
REPEAT
|
122
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+
|
123
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+
FETCH CUR INTO a;
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124
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+
|
125
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+
IF NOT done THEN
|
126
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+
|
127
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+
SET @id=a;
|
128
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+
|
129
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+
SET @sql='UPDATE tbl as a1,tbl as a2,tbl as a3 SET a1.l=a2.l+1,a1.r=a2.l+2,a1.level=a2.level+1,a2.r=a2.r+2,a3.r=a3.r+2 WHERE a1.parent_id=a2.id AND a2.l<a3.r AND a1.id=?';
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130
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+
|
131
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+
/* 子のlに親の1+1、子のrに親のl+2,子のlevelに親のlevel+1親のrを2増やす、親のlより大きいrを2増やす */
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132
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+
|
133
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+
|
134
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+
|
135
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+
PREPARE stmt from @sql;
|
136
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+
|
137
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+
EXECUTE stmt USING @id;
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138
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+
|
139
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+
SET @sql='UPDATE tbl as a1,tbl as a2,tbl as a3 SET a3.l=a3.l+2 WHERE a1.parent_id=a2.id AND a2.l<a3.l and a3.id!=a1.id AND a1.id=?';
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140
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+
|
141
|
+
/* 親の1より大きいlの内、子以外のものを2増やす */
|
142
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+
|
143
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+
|
144
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+
|
145
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+
PREPARE stmt from @sql;
|
146
|
+
|
147
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+
EXECUTE stmt USING @id;
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148
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+
|
149
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+
END IF;
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150
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+
|
151
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+
UNTIL done END REPEAT;
|
152
|
+
|
153
|
+
CLOSE CUR;
|
154
|
+
|
155
|
+
END
|
156
|
+
|
157
|
+
//
|
158
|
+
|
159
|
+
DELIMITER ;
|
160
|
+
|
161
|
+
|
162
|
+
|
163
|
+
```
|
164
|
+
|
165
|
+
プロシージャの呼び出し
|
166
|
+
|
167
|
+
元データを追加・削除・更新する度にプロシージャを呼び出してコンバートしてください
|
168
|
+
|
169
|
+
```SQL
|
170
|
+
|
171
|
+
CALL SET_LR;
|
172
|
+
|
173
|
+
```
|
174
|
+
|
175
|
+
|
176
|
+
|
177
|
+
nameを階層で表示し、含まれる子要素数を表示
|
178
|
+
|
179
|
+
COUNT1は直接の子要素数のみ、COUNT2は孫以降の要素数も含む
|
180
|
+
|
181
|
+
```SQL
|
182
|
+
|
183
|
+
SELECT CONCAT( REPEAT( "__", t1.level -1 ) , t1.name ) AS name
|
184
|
+
|
185
|
+
,(SELECT count(*)-1 from tbl as t3 WHERE t3.l BETWEEN t1.l AND t1.r and t3.level<=t1.level+1) AS COUNT1
|
186
|
+
|
187
|
+
,(SELECT count(*)-1 from tbl as t2 WHERE t2.l BETWEEN t1.l AND t1.r) AS COUNT1
|
188
|
+
|
189
|
+
FROM tbl as t2
|
190
|
+
|
191
|
+
ORDER BY t1.l
|
192
|
+
|
193
|
+
```
|
194
|
+
|
195
|
+
|
1
追記
test
CHANGED
@@ -4,6 +4,8 @@
|
|
4
4
|
|
5
5
|
- コンテンツ数とは何を指しますか?
|
6
6
|
|
7
|
+
- 13番目の要素のidが14で、14番目の要素とかぶっていますがよいのですか?
|
8
|
+
|
7
9
|
|
8
10
|
|
9
11
|
基本的にご提示されている「経路列挙モデル」より「隣接モデル」で
|