回答編集履歴
6
修正
test
CHANGED
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@@ -10,7 +10,7 @@
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array = ([(1..n).to_a] * m)
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array = ([(1..n).to_a] * m) # array = [[1, 2, 3], [1, 2]]等もいける。
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5
修正
test
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@@ -45,3 +45,123 @@
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作れていると思います。
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（私は数学が得意ではないのでよく分かっていません。）
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repeated_combinationを使う方法と私の方法では結果が若干異なります。
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```Ruby
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54
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# encoding: utf-8
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56
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m = 2
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n = 2
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array = ([(1..n).to_a] * m)
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tmp = array.shift
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array.each do |element|
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tmp = tmp.product(element)
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end
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tmp.map!(&:flatten)
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tmp.each do |e|
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puts "#{e} => #{e.reduce(:*)}"
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end
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```
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```
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[1, 1] => 1
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[1, 2] => 2
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[2, 1] => 2
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[2, 2] => 4
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```
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```Ruby
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# encoding: utf-8
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n = 2
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m = 2
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(1..n).to_a.repeated_combination(m){|comb|
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p comb
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}
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```
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```
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[1, 1]
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[1, 2]
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[2, 2]
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```
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```Ruby
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# encoding: utf-8
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(1..2).each do |i|
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(1..2).each do |j|
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p [i, j]
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end
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end
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```
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```
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[1, 1]
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[1, 2]
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[2, 1]
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[2, 2]
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```
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4
修正
test
CHANGED
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@@ -4,9 +4,9 @@
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4
4
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5
5
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6
6
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m = 4
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n = 3
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8
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-
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m = 4
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12
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@@ -32,7 +32,7 @@
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32
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tmp.each do |e|
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34
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35
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-
puts "#{e
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puts "#{e} => #{e.reduce(:*)}"
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end
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38
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3
修正
test
CHANGED
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@@ -4,7 +4,13 @@
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4
4
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5
5
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6
6
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7
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n = 3
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8
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m = 4
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11
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12
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7
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-
array = ([(1..
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array = ([(1..n).to_a] * m)
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8
14
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9
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10
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@@ -26,16 +32,16 @@
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26
32
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33
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tmp.each do |e|
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34
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29
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-
puts e.reduce(:*)
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puts "#{e.to_s} => #{e.reduce(:*)}"
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30
36
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end
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32
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-
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-
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35
39
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```
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36
40
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37
41
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再帰ではないですが、考えてみました。
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38
42
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43
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+
恐らく「i * j * ... * m」この部分のすべての組み合わせを
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44
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+
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|
39
|
-
|
|
45
|
+
作れていると思います。
|
|
40
46
|
|
|
41
47
|
（私は数学が得意ではないのでよく分かっていません。）
|
2
修正
test
CHANGED
|
@@ -4,7 +4,7 @@
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4
4
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5
5
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6
6
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7
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-
array = ([(1..
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7
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+
array = ([(1..5).to_a] * 3)
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8
8
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9
9
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10
10
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1
修正
test
CHANGED
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@@ -1,10 +1,10 @@
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1
1
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```Ruby
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2
2
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3
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-
#encoding: utf-8
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3
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+
# encoding: utf-8
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4
4
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5
5
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6
6
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7
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-
array = ([(1..
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7
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array = ([(1..8).to_a] * 3)
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8
8
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9
9
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10
10
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@@ -20,7 +20,7 @@
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20
20
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21
21
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22
22
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23
|
-
tmp.map!
|
|
23
|
+
tmp.map!(&:flatten)
|
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24
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25
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26
26
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