回答編集履歴
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sample
answer
CHANGED
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@@ -2,4 +2,44 @@
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2
2
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- JSONで予めHTMLに渡しておいて絞り込んで表示
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3
3
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- ajaxで都度サーバーに読みに行って表示
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4
4
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5
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-
のどちらかが妥当でしょう
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5
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のどちらかが妥当でしょう
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6
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# sample
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7
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一応テーブルの内容をみて変更する方法をsampleでつけておきます
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8
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9
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```javascript
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10
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<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
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11
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<script>
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12
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$(function(){
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13
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$('input[type=radio][name=gender]').on('change',function(){
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14
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var val=$(this).val();
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15
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if(val!==""){
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16
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$('tbody tr').hide().filter(function(){return $(this).find('td:eq(2)').text()==val}).show();
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17
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}else{
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18
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$('tbody tr').show();
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19
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}
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20
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});
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21
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});
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22
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</script>
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23
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24
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<input type="radio" name="gender" value="" checked>選択しない
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25
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<input type="radio" name="gender" value="男">男
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26
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<input type="radio" name="gender" value="女">女
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27
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<?PHP
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28
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$list = array(
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29
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"1"=>array("name"=>'Aさん',"age"=>20,"gender"=>'男'),
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30
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"2"=>array("name"=>'Bさん',"age"=>21,"gender"=>'女'),
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31
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"3"=>array("name"=>'Cさん',"age"=>22,"gender"=>'男'),
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32
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"4"=>array("name"=>'Dさん',"age"=>23,"gender"=>'女'),
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33
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"5"=>array("name"=>'Eさん',"age"=>24,"gender"=>'男'),
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34
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);
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35
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echo "<table><thead><tr><th>名前</th><th>年齢</th><th>性別</th></tr></thead><tbody>";
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36
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foreach($list as $key => $value){
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37
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echo "<tr>";
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38
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echo "<td>".$value["name"]."</td>";
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39
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echo "<td>".$value["age"]."</td>";
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40
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echo "<td>".$value["gender"]."</td>";
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41
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echo "</tr>";
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42
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}
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43
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echo "</tbody></table>";
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44
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?>
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45
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```
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