回答編集履歴
3
\[\]\.concatは不要だった
answer
CHANGED
@@ -2,7 +2,7 @@
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2
2
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```js
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3
3
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const threshold = 4;
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4
4
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let arr = [...Array(11).keys()]; // [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
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5
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-
let result =
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5
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+
let result = arr.filter(v => v >= threshold).concat(arr.filter(v => v < threshold)));
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6
6
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console.log(result);
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7
7
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// [4, 5, 6, 7, 8, 9, 10, 0, 1, 2, 3]
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8
8
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```
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2
10が抜けてた
answer
CHANGED
@@ -4,5 +4,5 @@
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4
4
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let arr = [...Array(11).keys()]; // [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
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5
5
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let result = [].concat(arr.filter(v => v >= threshold), arr.filter(v => v < threshold));
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6
6
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console.log(result);
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7
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-
// [4, 5, 6, 7, 8, 9, 0, 1, 2, 3]
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7
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+
// [4, 5, 6, 7, 8, 9, 10, 0, 1, 2, 3]
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8
8
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```
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1
ES6に
answer
CHANGED
@@ -1,8 +1,8 @@
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1
1
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これじゃダメ?w
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2
2
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```js
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3
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-
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3
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+
const threshold = 4;
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4
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-
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4
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+
let arr = [...Array(11).keys()]; // [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
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5
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-
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5
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+
let result = [].concat(arr.filter(v => v >= threshold), arr.filter(v => v < threshold));
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6
6
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console.log(result);
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7
7
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// [4, 5, 6, 7, 8, 9, 0, 1, 2, 3]
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8
8
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```
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