質問編集履歴
1
PHP内変数名が間違っていたため修正
    
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         @@ -62,8 +62,8 @@ 
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       62 
62 
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                try {
         
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       63 
63 
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                    $dsn = 'pgsql:dbname=postgres host=localhost port=5432';
         
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       64 
64 
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                    $user = 'postgres';
         
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       65 
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                    $ 
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 65 
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                    $passwords = ''; //こちらpasswordsの間違いです、申し訳ありません
         
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       66 
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                    $dbh = new PDO($dsn, $user, $ 
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 66 
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                    $dbh = new PDO($dsn, $user, $passwords);
         
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       67 
67 
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                    return "正常値";
         
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       68 
68 
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                }catch(PDOException $e){
         
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       69 
69 
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                    return "エラー";
         
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