質問編集履歴
3
sqlの追加
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@@ -22,9 +22,44 @@
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SUM(CASE WHEN come_place='退場' THEN 1 END) AS 退場済み,
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SUM(1)
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FROM
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FROM table
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GROUP BY e_id,to_date(come_date,'yyyy/mm/dd')
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ORDER BY e_id
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```
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case whenを使いましたが入場中をどのように書けばよいかわかりません
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入場中とは、入場記録があるが同日の退場記録がない状態です
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入場中とは、入場記録があるが同日の退場記録がない状態です
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追記
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いろいろやってみて
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```lang-sql
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SELECT
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TO_CHAR(to_date,'yyyy/mm/dd') as date
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,extract(dow from to_date)
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,(array['(日)','(月)','(火)','(水)','(木)','(金)','(土)'])[extract(dow from to_date) + 1] as days
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,SUM(
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SUM(CASE WHEN in1 > 1 AND out1 != 0 THEN 1 END ) + SUM(CASE WHEN out1 > 0 THEN 1 END )
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) as "総来場組数"
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FROM (
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SELECT
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TO_CHAR(to_date,'yyyy/mm/dd') as date
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,extract(dow from to_date)
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,(array['(日)','(月)','(火)','(水)','(木)','(金)','(土)'])[extract(dow from to_date) + 1] as days
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,SUM(CASE WHEN in1 > 0 THEN 1 END) as "来場済み"
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,SUM(CASE WHEN out1 > 0 THEN 1 END ) as "退場済み"
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,SUM(CASE WHEN in1 > 1 AND out1 != 0 THEN 1 END ) as "来場中"
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FROM (
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SELECT e_id,to_date(come_date,'yyyy/mm/dd'),
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SUM(CASE WHEN come_place='来場' THEN 1 ELSE 0 END) AS in1
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,SUM(CASE WHEN come_place='退場' THEN 1 ELSE 0 END) AS out1
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FROM table
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GROUP BY e_id,to_date(come_date,'yyyy/mm/dd')
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)as t2
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) as t1
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GROUP BY to_date
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ORDER BY date
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```
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ERROR: 列"t2.to_date"はGROUP BY句で出現しなければならないか、集約関数内で使用しなければなりません
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LINE 2: TO_CHAR(to_date,'yyyy/mm/dd') as date
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となります。
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case whenの詳しい使い方
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ORDER BY date
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```
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前回作ったのは入退場全部含めて一括で表示していました
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前回作ったのは入退場全部含めて一括で表示していました
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```lang-sql
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SELECT e_id,to_date(come_date,'yyyy/mm/dd'),
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SUM(CASE WHEN come_place='入場' THEN 1 END) AS 入場済み,
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SUM(CASE WHEN come_place='退場' THEN 1 END) AS 退場済み,
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SUM(1)
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FROM qpass_s_come_00001289
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GROUP BY e_id,to_date(come_date,'yyyy/mm/dd')
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ORDER BY e_id
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```
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case whenを使いましたが入場中をどのように書けばよいかわかりません
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30
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入場中とは、入場記録があるが同日の退場記録がない状態です
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1
sql
title
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File without changes
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body
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@@ -1,3 +1,18 @@
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1
1
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テーブルに入場、退場、未のステータスがあるとします。
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入場済み、入場中、退場済み、総来場組数の件数を出したいのですが
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どのようなsqlをつくればよいですか
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どのようなsqlをつくればよいですか
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```lang-sql
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SELECT TO_CHAR(to_date,'yyyy/mm/dd') as date
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,extract(dow from to_date)
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,(array['(日)','(月)','(火)','(水)','(木)','(金)','(土)'])[extract(dow from to_date) + 1] as days
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,count(*) FROM (
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SELECT e_id,to_date(come_date,'yyyy/mm/dd'),COUNT(*)
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FROM $table_come
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GROUP BY e_id,to_date(come_date,'yyyy/mm/dd')
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) as t1
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GROUP BY to_date
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ORDER BY date
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```
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前回作ったのは入退場全部含めて一括で表示していました
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