質問編集履歴
2
タグ変更
test
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test
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1
コード、タグ変更
test
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test
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@@ -2,11 +2,7 @@
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5
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調べてたり何度試したりしましたが、
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調べてたり何度試したりしましたが、今のところ各u=0.0;となります。
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が出ます。
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6
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11
7
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8
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@@ -20,4 +16,100 @@
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u(0,t) = u(1,t) =0, t∈(0,T),
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u(x,0) = sinπx, x∈(0,
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u(x,0) = sinπx, x∈(0,
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```public class ex{
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static public void main(String[] args){
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double a = 0.0; double b = 1.0;
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int M = 10;
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double dx = (b-a)/(double)M;
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double T = 1.0;
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double t = 0.0;
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double x = 0.0;
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double dt = 0.5*dx*dx;
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double err= 0.0;
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int N = (int)(T/dt);
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double ua = 0.0; double ub = 0.0;
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double []u = new double[M+1];
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double []v = new double[M+1];
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for(int j=0; j<M+1; j++){
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u[j]=Math.sin(Math.PI*x);
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}
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for (int k=0; k<N+1; k++){
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for (int j=0; j<M-1; j++){
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x = x + dx*((double)j);
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v[j+1] = u[j+1] + (u[j+2] - 2*u[j+1] + u[j])*100*0.005;
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t = t + dt;
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}
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u = v;
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for (int j=0; j<M+1; j++){
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if (k == 5*(int)(k/5)){
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System.out.println(" t = "+t+", u["+j+"]= "+u[j]);
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}
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if(err < Math.abs(u[j] - exact(t,x))){
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err= Math.abs(u[j] - exact(t,x));
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System.out.println(" Error = "+err);
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}
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}
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}
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}
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public static double exact(double t, double x){
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double exact;
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exact = Math.exp(-Math.PI*Math.PI*t)* Math.sin(Math.PI*x);
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return exact;
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}
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}
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```1).
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