質問編集履歴
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理解できないのはソースの以下の箇所です。
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https://github.com/vercel/swr/blob/master/src/types.ts#L6-L32
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[https://github.com/vercel/swr/blob/master/src/types.ts#L6-L32](https://github.com/vercel/swr/blob/master/src/types.ts#L6-L32)
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```typescript
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export type Fetcher<Data = unknown, SWRKey extends Key = Key> =
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なぜneverの分岐に入らずこのような動作になるのでしょうか。
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ご教示いただけると大変助かります。
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よろしくお願いいたします。
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よろしくお願いいたします。
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## useSWRの定義
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追っていくと以下にあたります。
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[https://github.com/vercel/swr/blob/da33f52633ef5bb357e074de8499c76661e23c78/src/use-swr.ts#L512](https://github.com/vercel/swr/blob/da33f52633ef5bb357e074de8499c76661e23c78/src/use-swr.ts#L512)
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`withArgs`自体の定義は以下です。
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[https://github.com/vercel/swr/blob/da33f52633ef5bb357e074de8499c76661e23c78/src/utils/resolve-args.ts#L11-L36](https://github.com/vercel/swr/blob/da33f52633ef5bb357e074de8499c76661e23c78/src/utils/resolve-args.ts#L11-L36)
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```typescript
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export const withArgs = <SWRType>(hook: any) => {
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return (((...args: any) => {
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// Normalize arguments.
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const [key, fn, _config] = normalize<any, any>(args)
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// Get the default and inherited configuration.
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const fallbackConfig = mergeObjects(
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defaultConfig,
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useContext(SWRConfigContext)
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)
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// Merge configurations.
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const config = mergeConfigs(fallbackConfig, _config)
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// Apply middleware
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let next = hook
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const { use } = config
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if (use) {
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for (let i = use.length; i-- > 0; ) {
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next = use[i](next)
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}
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}
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return next(key, fn || config.fetcher, config)
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}) as unknown) as SWRType
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}
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```
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