質問編集履歴
4
解決方法の追記
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### 解決方法
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```
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df.assign(C=-df.reset_index().groupby('index').apply(lambda sdf: sdf.sort_values('順位')['得点'].diff(-1).sort_index()).to_numpy())
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3
教えて頂いたコードの実行結果報告のため
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```
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### 現在の状況 2
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C列の計算結果は正しい数値が取得できました。ありがとうございます
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あとは、DataFrameの構造をもとに戻す方法と、やり方が見えてきたので崩さずに追加できないか模索してみます！
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df2 = df.reset_index()
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df2 = df2.rename(columns={'index':'group'})
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temp_df = df2.set_index(['group', '順位'])
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new_df = temp_df.assign(C=(temp_df.rename(index=lambda s: s-1, level=1) - temp_df)).reset_index()
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new_df.head(20)
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group 順位 得点 C
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0 201901010101 1.0 1.4 2.1
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1 201901010101 2.0 3.5 6.2
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2 201901010101 6.0 46.6 10.2
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3 201901010101 7.0 56.8 57.9
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4 201901010101 9.0 140.3 NaN
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5 201901010101 3.0 9.7 6.7
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6 201901010101 8.0 114.7 25.6
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7 201901010101 5.0 26.1 20.5
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8 201901010101 4.0 16.4 9.7
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9 201901010102 4.0 4.3 9.6
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10 201901010102 6.0 19.8 7.2
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11 201901010102 5.0 13.9 5.9
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12 201901010102 8.0 27.2 NaN
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13 201901010102 2.0 4.1 0.1
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14 201901010102 7.0 27.0 0.2
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15 201901010102 1.0 2.9 1.2
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16 201901010102 3.0 4.2 0.1
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18 201901010103 1.0 3.6 NaN
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19 201901010103 7.0 14.0 NaN
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```
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2
誤字
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順位 得点
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順位 得点 C
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1
教えて頂いたコードの実行結果の追記
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一気にできる方法などありましたら、ご教授いただけますでしょうか
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### 現在の状況 １
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昨日に頂いたコードを実行しました。
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ありがとうございます。
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目標）
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indexのグループ別に、次の順位の人との得点の差を求めたいです
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結果）
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順位の最大数がindex別に変わるためだと思いますが、数値がずれるようです
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```
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df.head(20)
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順位 得点
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```
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実行と結果になります。
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```
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df2 = df.reset_index()
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df2['C'] = 0
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for i in range(max(df['順位'].astype(int))):
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df2['shift_index'] = df2['index'].shift(-i-1)
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df2['shift_B'] = df2['得点'].shift(-i-1)
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df2['C'] = df2['C'].mask((df2['順位']==i+1) & (df2['index']==df2['shift_index']), df2['shift_B']-df2['得点'])
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df3 = df2.drop(['shift_index', 'shift_B'], axis=1).set_index('index')
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```
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