質問編集履歴

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2020/11/08 10:26

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sequelanonymous
sequelanonymous

スコア123

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  A[3] = 3, the non-divisors are: 2, 6,したがって割り切れない数値は2個
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  A[4] = 6, there aren't any non-divisors.したがって割り切れない数値は0個
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+ *参照URL
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+ [stackoverflow](https://stackoverflow.com/questions/59322140/codility-countnondivisible-python-better-performance)