質問編集履歴
3
説明の追加
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@@ -27,7 +27,11 @@
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#参考質問
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https://qiita.com/tibigame/items/aebbac176d9bbdaf3d15
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#公式。やりたいこと
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条件
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f(x,y)=(x^2+xy+y^2)log(x^2+y^2) :((x,y)≠(0,0))
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= 0 :((x,y)=(0,0))
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公式
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fx(0,0)= lim h->0 ( f(h,0)-f(0,0))/h
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= lim h->0 ( h^2log(h^2))/h
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=lim h->0 (-2h) =0
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説明追加
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print('{0}'.format(f_x))
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```
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#参考質問
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https://qiita.com/tibigame/items/aebbac176d9bbdaf3d15
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28
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https://qiita.com/tibigame/items/aebbac176d9bbdaf3d15
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29
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#公式。やりたいこと
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30
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+
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31
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fx(0,0)= lim h->0 ( f(h,0)-f(0,0))/h
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= lim h->0 ( h^2log(h^2))/h
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=lim h->0 (-2h) =0
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tex形式で書きたかったのですが分かりづらくて申し訳ありません
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1
忘れた部分があったから
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#原点でｘに関して偏微分する
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f_x=(aa.subs([(x,h),(y,0)]).trigsimp()-aa.subs([(x,0),(y,0)]).trigsimp())/h
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print('{0}'.format(f_x))
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```
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```
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#参考質問
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28
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https://qiita.com/tibigame/items/aebbac176d9bbdaf3d15
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