質問編集履歴
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情報を追記いたしました
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Rails
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Rails 取得したデータの整形
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Rails で質問させてください。
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異なる２つのテーブル（モデル）を union で結合して取得した下記
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異なる２つのテーブル（モデル）を union で結合して取得した下記取得データの before のようなデータを下記取得データのafterような形に整形して取得することは可能でしょうか？
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やりたいこととしては、
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・"type" が "1" のデータは、"child_id", "child_name", "child_period", "child_note", "child_done", "child_order_number" を削除してしまう。
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@@ -9,7 +9,48 @@
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やり方をご教授いただけますと幸いです。
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##model
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```rb
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class Project < ApplicationRecord
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has_many :todos, dependent: :destroy
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accepts_nested_attributes_for :todos, allow_destroy: true
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has_many :tasks, dependent: :destroy
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accepts_nested_attributes_for :tasks
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def self.getCombineTodos(project_id)
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sql = <<-EOS
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(select '1' as type_flg, pt.pt_id as id, pt.name as name, pt.period, pt.note, pt.done, pt.order_number, 0 as child_id, 0 as child_name, 0 as child_period, 0 as child_note, 0 as child_done, 0 as child_order_number from (select project_todos.id + 100000000 as pt_id, project_id, period, project_todos.note, done, project_todos.name as name, order_number from project_todos where project_todos.project_id = :project_id) as pt)
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union
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(select '2' as type_flg, pt.id + 200000000, pt.name, pt.period, pt.note, pt.done, pt.order_number, ptt.id as child_id, ptt.name as child_name, ptt.period, ptt.note as chile_note, ptt.done as child_done, ptt.order_number as child_order_number from project_tasks as pt
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left outer join project_task_todos as ptt on pt.id = ptt.project_task_id where pt.project_id = :project_id) ORDER BY order_number ASC
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EOS
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find_by_sql([sql, { project_id: project_id }])
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end
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end
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```
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##controller
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上記のmodel内のsqlで取得できるデータを、下記のメソッドで、フロント(Vue)側に渡します。
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```
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# todoとtaskをまとめて同列にして取得
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def combine_todos
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project = Project.getCombineTodos(params[:id])
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render json: {
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status: 'SUCCESS',
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message: '',
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data: project
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}
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end
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```
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##取得データ
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```before
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"data":[
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{
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@@ -183,6 +224,9 @@
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]
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```
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####捕捉
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ruby-2.6.2
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Ruby on Rails 5.2.3
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