質問編集履歴
2
事例を追加しました
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```
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【追加質問です】
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６次元のデータを使った例です。
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numpy の場合、out = x.transpose(0, 4, 5, 1, 2, 3) です。
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```JavaScript
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<script>
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// 例 x:入力 ６次元配列(1x1x3x3x4x4)
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// -> out :出力 ６次元配列(1x4x4x1x3x3) へ軸変換
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x=[
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[[
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// *
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[
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[
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[1,1,1,1],
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[1,1,1,1],
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[1,1,1,1],
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[1,1,1,1],
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],
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[
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[1,1,1,1],
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[1,1,1,1],
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[1,1,1,1],
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[1,1,1,1],
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],
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[
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[1,1,1,1],
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[1,1,1,1],
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[1,1,1,1],
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[1,1,1,1],
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],
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],
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// **
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[
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[
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[1,1,1,1],
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[1,1,1,1],
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[1,1,1,1],
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[1,1,1,1],
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],
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[
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[1,1,1,1],
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[1,1,1,1],
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[1,1,1,1],
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[1,1,1,1],
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],
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[
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[1,1,1,1],
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[1,1,1,1],
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[1,1,1,1],
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[1,1,1,1],
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],
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],
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// ***
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[
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[
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[1,1,1,1],
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[1,1,1,1],
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[1,1,1,1],
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[1,1,1,1],
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],
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[
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[1,1,1,1],
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[1,1,1,1],
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[1,1,1,1],
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[1,1,1,1],
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],
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[
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[1,1,1,1],
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[1,1,1,1],
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[1,1,1,1],
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[1,1,1,1],
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],
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],
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]]
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]
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console.log(x)
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let out = []
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for (let d0 = 0 ; d0 < x.length; d0++){//1
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out[d0] = []
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for (let d1 = 0 ; d1 < x[0][0][0][0].length ; d1++){//4
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out[d0][d1] = []
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for (let d2 = 0 ; d2 < x[0][0][0][0][0].length ; d2++){//4
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out[d0][d1][d2] = []
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for (let d3 = 0 ; d3 < x[0].length ; d3++){//1
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out[d0][d1][d2][d3] = []
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for (let d4 = 0 ; d4 < x[0][0].length ; d4++){//3
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out[d0][d1][d2][d3][d4] = []
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for (let d5 = 0 ; d5 < x[0][0][0].length ; d5++){//3
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console.log(`out[${d0}][${d1}][${d2}][${d3}][${d4}][${d5}] = ${x[d0][d4][d5][d1][d2][d3]}`);
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out[d0][d1][d2][d3][d4][d5] = x[d0][d4][d5][d1][d2][d3]
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}
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}
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}
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}
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}
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}
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console.log(out)
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</script>
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```
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実行すると、
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Uncaught TypeError: Cannot read property '0' of undefined
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のエラーでストップします。
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1
例題の追加
title
CHANGED
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File without changes
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body
CHANGED
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@@ -2,8 +2,9 @@
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2
2
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3
3
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以下のようなn次元配列A (1x2x3x4)を 軸を入れ替えて 例えばn次元配列[3x4x1x2]にするのが transposeメソッドですが、これをfor文で書くとどうなりますか？
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4
4
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5
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```JavaScript
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5
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-
例
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6
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// 例 x:入力
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6
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-
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x=[
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[
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[
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[1,2,3,4],
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@@ -16,4 +17,22 @@
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[9,10,11,12],
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],
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]
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]
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]
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// 出力:out
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// 初期化
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let out = []
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for (let d0 = 0 ; d0 < x[0][0].length; d0++){
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out[d0] = []
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for (let d1 = 0 ; d1 < x[0][0][0].length ; d1++){
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out[d0][d1] = []
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for (let d2 = 0 ; d2 < x.length ; d2++){
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out[d0][d1][d2] = []
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for (let d3 = 0 ; d3 < x[0].length ; d3++){
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out[d0][d1][d2][d3] = 0
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}
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}
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}
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}
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```
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