質問編集履歴
3
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こんなかんじでしょうか?
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'''
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import UIKit
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class ViewController: UIViewController,UIPickerViewDataSource,UIPickerViewDelegate {
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let city = ["London","Newyork","shanghai","hongkong"]
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func numberOfComponents(in pickerView: UIPickerView) -> Int {
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return 1
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}
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func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
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return city.count
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}
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func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
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return city[row]
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}
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func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
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}
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@IBOutlet weak var picker: UIPickerView!
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@IBAction func showw(_ sender: AnyObject) {
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picker.selectedRow(inComponent:0)
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performSegue(withIdentifier: "London", sender: self)
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performSegue(withIdentifier: "Newyork", sender: self)
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performSegue(withIdentifier: "shanghai", sender: self)
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performSegue(withIdentifier: "hongkong", sender: self)
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let aa:Int = picker.selectedRow(inComponent: 0)
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switch aa {
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case 0:
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performSegue(withIdentifier: "hongkong", sender: self)
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case 1:
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performSegue(withIdentifier: "sendai", sender: self)
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case 2:
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performSegue(withIdentifier: "shanghai", sender: self)
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default:
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return
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} }
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override func viewDidLoad() {
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super.viewDidLoad()
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picker.delegate = self
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picker.dataSource = self
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}
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}
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switch文のところはどうすれば正解なのですか?
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performSegueを使えばそのIdentifierのところへいけるのはわかったのですが、pickerviewの選択したあとどうやれば画面遷移できるのでしょうか?
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'''import UIKit
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class ViewController: UIViewController,UIPickerViewDataSource,UIPickerViewDelegate {
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@@ -56,5 +56,4 @@
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}
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'''
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"""追加
title
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body
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@@ -3,7 +3,7 @@
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performSegueを使えばそのIdentifierのところへいけるのはわかったのですが、pickerviewの選択したあとどうやれば画面遷移できるのでしょうか?
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import UIKit
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"""import UIKit
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class ViewController: UIViewController,UIPickerViewDataSource,UIPickerViewDelegate {
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@@ -55,4 +55,6 @@
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}
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}
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}
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"""
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