質問編集履歴
2
htmlの追加
test
CHANGED
File without changes
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test
CHANGED
@@ -27,6 +27,12 @@
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27
27
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28
28
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29
29
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</script>
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30
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+
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31
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```
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32
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+
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33
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+
```html
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34
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+
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35
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+
<div class="search"></div>
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30
36
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31
37
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```
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32
38
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1
ソースコードの追加
test
CHANGED
File without changes
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test
CHANGED
@@ -2,4 +2,98 @@
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2
2
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3
3
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4
4
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5
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+
呼び出し先と同じものを呼び出し元で使用すると受け取れるのですが、
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6
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+
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7
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+
呼び出し先でうまく表示できません
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8
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+
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9
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+
|
10
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+
|
5
11
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よろしければ教えてください。
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12
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+
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13
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+
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14
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+
|
15
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+
呼び出し元
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16
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+
|
17
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+
```JQuery
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18
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+
|
19
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+
<script type="text/javascript">
|
20
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+
|
21
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+
$(function() {
|
22
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+
|
23
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+
$(".search").load("include/search.php");
|
24
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+
|
25
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+
});
|
26
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+
|
27
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+
|
28
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+
|
29
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+
</script>
|
30
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+
|
31
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+
```
|
32
|
+
|
33
|
+
|
34
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+
|
35
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+
呼び出し先 search.php
|
36
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+
|
37
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+
```PHP
|
38
|
+
|
39
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+
<?php
|
40
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+
|
41
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+
$year = date("Y");
|
42
|
+
|
43
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+
$month = date("n");
|
44
|
+
|
45
|
+
$day = date("j");
|
46
|
+
|
47
|
+
$date="";
|
48
|
+
|
49
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+
if(isset($_GET["year"]) && isset($_GET["month"]) && isset($_GET["day"])){
|
50
|
+
|
51
|
+
$year = $_GET["year"];
|
52
|
+
|
53
|
+
$month = $_GET["month"];
|
54
|
+
|
55
|
+
$day = $_GET["day"];
|
56
|
+
|
57
|
+
}
|
58
|
+
|
59
|
+
if(isset($_GET["date"])){
|
60
|
+
|
61
|
+
$date= $_GET["date"];
|
62
|
+
|
63
|
+
}
|
64
|
+
|
65
|
+
|
66
|
+
|
67
|
+
echo $year.$month.$day.$date;
|
68
|
+
|
69
|
+
?>
|
70
|
+
|
71
|
+
```
|
72
|
+
|
73
|
+
|
74
|
+
|
75
|
+
```html
|
76
|
+
|
77
|
+
<form method="get">
|
78
|
+
|
79
|
+
<div id="search-bar">
|
80
|
+
|
81
|
+
<select name="year" id="bar_year" class="sel_year">
|
82
|
+
|
83
|
+
</select>年
|
84
|
+
|
85
|
+
<select name="month" id="bar_month" class="sel_month">
|
86
|
+
|
87
|
+
</select>月
|
88
|
+
|
89
|
+
<select name="day" id="bar_day" class="sel_day">
|
90
|
+
|
91
|
+
</select>日
|
92
|
+
|
93
|
+
<button id="search-button">検索</button>
|
94
|
+
|
95
|
+
</div>
|
96
|
+
|
97
|
+
</form>
|
98
|
+
|
99
|
+
```
|