質問編集履歴
2
完成コードを追加
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@@ -91,4 +91,22 @@
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91
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mysql -V => `mysql Ver 14.14 Distrib 5.7.23`
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php -V => `PHP 7.0.32-0ubuntu0.16.04.1`
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-
OS => `Linux 4.4.0-133-generic #159-Ubuntu`
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OS => `Linux 4.4.0-133-generic #159-Ubuntu`
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###追記
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指摘を受けた後に直したコード(login.php)
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```PHP
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/* query DB */
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$UID=$_POST["userPassword"];
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$pass=$_POST["password"];
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$query = "select exists(select * from db where userID='$UID' and password='$pass')";
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$result = $mysqli->query($query);
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if($result->fetch_assoc()){
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echo "User $UID have successfully logged in!!" . "<br>";
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}
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else {
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echo "Could not find user $UID" . "<br>";
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}
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```
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1
コード訂正
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@@ -73,7 +73,7 @@
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+------------------+----------+-----------+---------------+----------+---------------+
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```
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######htmlに表示される内容
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######htmlに表示される内容(ID:5bd70d70add61, pass:XXXXXでログインするがXXXXXのパスワードはテーブルに無いにも関わらずログインに成功)
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```
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Connect success!
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id : 5bd70d70add61
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