質問編集履歴
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@@ -31,4 +31,34 @@
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// もう一度重複要素を除去する => ["B", "D"]
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34
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```
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### 解決方法＆備忘録
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37
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その1
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```swift
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let array = ["A", "B", "B", "B", "C", "D", "D"]
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// 重複している要素の取得
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var set = Set<String>()
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let duplicatedEArray = NSOrderedSet(array: array.filter { !set.insert($0).inserted }).array as! [String]
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// => ["B", "D"]
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// ユニークな要素の取得
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let noDuplicatedArray = NSOrderedSet(array: array).array as! [String]
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let UniqueEArray = noDuplicatedArray.filter{ v in return !duplicatedEArray.contains(v) }
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// => ["A", "C"]
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```
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その2
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```swift
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let array = ["A", "B", "B", "B", "C", "D", "D"]
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// 重複している要素の取得
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let duplicatedEArray = Array(Dictionary(grouping: array) {$0}.filter {$0.value.count > 1}.keys)
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// => ["B", "D"]
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// ユニークな要素の取得
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let UniqueEArray = Array(Dictionary(grouping: array) {$0}.filter {$0.value.count == 1}.keys)
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// => ["A", "C"]
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```
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