質問編集履歴
5
test
CHANGED
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@@ -1 +1 @@
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1
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-
関数Aの実行結果がnullかundefinedのみに関数内に変数を新たに作らず、関数Bを実行させるには？
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1
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+
関数Aの実行結果がnullかundefinedの時のみに関数内に変数を新たに作らず、関数Bを実行させるには？
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test
CHANGED
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File without changes
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4
`foo(v)`をこのように２回呼ぶことも出来るでしょうが、これは非効率なので避けたいところです。
test
CHANGED
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File without changes
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test
CHANGED
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@@ -52,6 +52,20 @@
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52
52
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53
53
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54
54
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55
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```
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56
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+
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57
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+
const hoge = (foo, bar) => (v) => {
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58
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+
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59
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+
return foo(v) != null ? foo(v) : bar(v);
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60
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+
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61
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+
}
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62
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+
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63
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+
```
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64
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+
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65
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+
`foo(v)`をこのように２回呼ぶことも出来るでしょうが、これは非効率なので避けたいところです。
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66
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+
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67
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+
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68
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+
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55
69
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```ここに言語を入力
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56
70
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57
71
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const hoge = (foo, bar) => (v) => foo(v) || bar(v);
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3
const zero = (v) => 0 * v; const double = (v) => 2 * v; console.log( hoge(zero, double)(10) )
test
CHANGED
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File without changes
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test
CHANGED
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@@ -16,23 +16,15 @@
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16
16
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17
17
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```
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18
18
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19
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+
const zero = (v) => 0 * v;
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20
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+
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21
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+
const double = (v) => 2 * v;
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22
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+
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23
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+
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24
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+
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19
25
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console.log(
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20
26
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21
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-
hoge(
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22
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-
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23
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-
function(v) {
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24
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-
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25
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-
return 0;
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26
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-
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27
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-
},
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28
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-
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29
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-
function(v) {
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30
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-
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31
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-
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27
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+
hoge(zero, double)(10)
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32
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-
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33
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-
}
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34
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-
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35
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-
)(10)
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36
28
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37
29
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)
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38
30
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2
const hoge = (foo, bar) => (v) => { const result = foo(v) return result != null ? result : bar(v);
test
CHANGED
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File without changes
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test
CHANGED
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@@ -44,23 +44,11 @@
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44
44
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45
45
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```
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46
46
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47
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-
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47
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+
const hoge = (foo, bar) => (v) => {
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48
48
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49
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-
ret
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49
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+
const result = foo(v)
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50
50
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51
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-
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51
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+
return result != null ? result : bar(v);
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52
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-
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53
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-
if (result != null) {
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54
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-
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55
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-
return result
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56
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-
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57
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-
} else {
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58
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-
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59
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-
return bar(v);
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60
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-
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61
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-
}
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62
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-
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63
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-
}
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64
52
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65
53
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}
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|
66
54
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1
const hoge = (foo, bar) => (v) => foo(v) || bar(v);
test
CHANGED
|
File without changes
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test
CHANGED
|
@@ -1,14 +1,6 @@
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1
1
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```ここに言語を入力
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2
2
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3
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-
function hoge(foo, bar) {
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4
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-
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5
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-
return function(v) {
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6
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-
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7
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-
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3
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+
const hoge = (foo, bar) => (v) => foo(v) || bar(v);
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8
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-
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|
9
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-
}
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|
10
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-
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|
11
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-
}
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12
4
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13
5
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```
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|
14
6
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@@ -82,15 +74,7 @@
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82
74
|
|
|
83
75
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```ここに言語を入力
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|
84
76
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85
|
-
function hoge(foo, bar) {
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86
|
-
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|
87
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-
return function(v) {
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|
88
|
-
|
|
89
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-
|
|
77
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+
const hoge = (foo, bar) => (v) => foo(v) || bar(v);
|
|
90
|
-
|
|
91
|
-
}
|
|
92
|
-
|
|
93
|
-
}
|
|
94
78
|
|
|
95
79
|
```
|
|
96
80
|
|