質問編集履歴
7
誤字
test
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test
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@@ -102,6 +102,6 @@
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102
102
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103
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|1 |aaa |ホワイト|
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104
104
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105
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-
このような結果になったのですが、clを,区切りに
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105
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このような結果になったのですが、clを,区切りにして1レコードに格納したいです。
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106
106
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よろしくお願いします。
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6
sql修正
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test
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@@ -72,22 +72,36 @@
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72
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表示する際のSQL
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74
74
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75
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+
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76
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+
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75
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```sql
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76
78
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77
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select
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79
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select user_id,name,colorname
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78
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-
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79
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,STRING_AGG(c.colorname,',') as color_name_list
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80
80
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81
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from(
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82
82
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83
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select *, value as c
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83
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select *, value as cl
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84
84
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85
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from sample outer apply string_split(s
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85
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from sample as s outer apply string_split(s.color,',')
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86
86
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87
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) a
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87
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+
) as a
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88
88
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89
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-
on c
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89
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+
inner join master_color as c
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90
90
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91
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-
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91
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on c.color_cd = a.cl
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92
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+
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93
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92
94
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93
95
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```
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96
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+
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97
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+
これで
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98
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+
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99
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|user_id|name |cl |
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100
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+
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101
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|1 |aaa |ブラック|
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102
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103
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|1 |aaa |ホワイト|
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104
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+
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105
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+
このような結果になったのですが、clを,区切りに戻したいのですがどうしたらいいのでしょうか？
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106
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+
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107
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+
よろしくお願いします。
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5
sql修正
test
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test
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@@ -74,12 +74,20 @@
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74
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75
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```sql
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76
76
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77
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select a.user_id,a.name
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77
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+
select a.user_id,a.name
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78
78
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79
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-
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79
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+
,STRING_AGG(c.colorname,',') as color_name_list
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80
80
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81
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-
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81
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+
from(
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82
82
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83
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select *, value as color
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84
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+
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85
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from sample outer apply string_split(sample.color,',')
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86
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+
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87
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+
) a inner join master_color as c
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88
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+
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83
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-
on c.color = a.color
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89
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+
on c.color_cd = a.color
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90
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+
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91
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+
group by a.user_id,a.name
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84
92
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85
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```
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4
修正
test
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File without changes
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test
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@@ -68,6 +68,10 @@
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68
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70
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71
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+
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72
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+
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73
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表示する際のSQL
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74
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+
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71
75
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```sql
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72
76
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73
77
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select a.user_id,a.name,c.colorname
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3
ソース追加
test
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File without changes
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test
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@@ -52,6 +52,22 @@
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52
52
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53
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```
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54
54
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55
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Controller
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56
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+
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57
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```php
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58
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59
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$colors = Request::Input('color');
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60
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+
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61
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+
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62
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+
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63
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+
//配列を文字列に変換してテーブルに登録しています。
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64
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+
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65
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+
$color = implode(",",$colors);
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66
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+
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67
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```
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68
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+
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69
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+
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70
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+
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55
71
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```sql
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56
72
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57
73
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select a.user_id,a.name,c.colorname
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2
追加
test
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File without changes
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test
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@@ -28,9 +28,11 @@
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28
28
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29
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表示する際に
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30
30
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31
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-
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31
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+
|user_id|name|color |
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32
32
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33
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-
|ブラック,ホワイト|
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33
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+
|01 |a |ブラック,ホワイト|
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34
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+
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35
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+
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34
36
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35
37
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と表示させたいです。
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36
38
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1
ソース追加
test
CHANGED
|
File without changes
|
test
CHANGED
|
@@ -49,3 +49,15 @@
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49
49
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50
50
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51
51
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```
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52
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+
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53
|
+
```sql
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|
54
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+
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|
55
|
+
select a.user_id,a.name,c.colorname
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|
56
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+
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|
57
|
+
from sample1 as a
|
|
58
|
+
|
|
59
|
+
inner join color as c
|
|
60
|
+
|
|
61
|
+
on c.color = a.color
|
|
62
|
+
|
|
63
|
+
```
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