質問編集履歴
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物質判定方法ゲーム理論
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なにか良い方法はありませんか？よろしくお願いします。
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namespace _1108_ボール_斜
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namespace _1108_ボール_斜
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{
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public partial class Formballshoot : Form
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{
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double ballPos_x;
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double ballPos_y;
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double vx = 10; //x座標の初速度
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double vy = -30; //y座標の初速度
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double g = 1.0; //加速度
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double power = 1;
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int t = 0; //時間
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int ballRadius = 10; //ボールの半径
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double deg; //打ちだし角度
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Timer timer = new Timer();
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Random rand = new Random(); //乱数を発生させるrandを生成
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public Formballshoot()
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{
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//角度を30度～60度の間で発生
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deg = rand.Next(30, 60);
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this.ballPos_x = 10; //x座標の初期位置
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this.ballPos_y = 650; //y座標の初期位置
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InitializeComponent();
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PictureBox1.Left = 150; //カゴのy座標の初期位置
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PictureBox1.Top = 500; //カゴのx座標の初期位置
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//マウスホイールイベントの追加
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this.MouseWheel += new System.Windows.Forms.MouseEventHandler(this.Scroll_MouseWheel);
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//タイマーイベント
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Timer timer = new Timer();
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timer.Interval = 50;
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timer.Tick += new EventHandler(Update);
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//timer.Start();
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}
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private void Update(object sender, EventArgs e)
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{
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ballPos_x += vx * Math.Cos(deg * (Math.PI / 180));
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ballPos_y += vy * Math.Sin(deg * (Math.PI / 180)) + g * t;
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this.t++;
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//再描写
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Invalidate();
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//ボールが画面の下を超えた場合
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//繰り返しボールを飛ばす
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if (ballPos_y > 650)
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{
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this.vx = power; //初速をpowerにする
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this.vy = -30; //y座標の初速度を再び示す
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this.g = 1.0; //加速度を再び示す
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this.ballPos_x = 10; //x座標の初期位置に戻す
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this.ballPos_y = 650; //y座標の初期位置に戻す
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deg = rand.Next(30, 60); //角度を30度～60度に設定
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this.t = 0;
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this.t++;
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ballPos_x += vx * Math.Cos(deg * (Math.PI / 180));
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ballPos_y += vy * Math.Sin(deg * (Math.PI / 180)) + g * t;
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}
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//ボールとカゴの当たり判定
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if ((ballPos_x > PictureBox1.Location.X) &&
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(ballPos_x < PictureBox1.Left + PictureBox1.Size.Width) &&
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(ballPos_y > PictureBox1.Location.Y) &&
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(ballPos_y < PictureBox1.Top + PictureBox1.Size.Height))
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{
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this.vx = -1;
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this.vy = -1;
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}
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}
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}
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