SAS proc SQL pivot変換 シンプルに書きたい

Question

SASのproc SQLでpivot変換しています。
現状、以下のプログラムで希望の出力を出せています。
「max(case when NO = # then ### end) as ##」の繰返しをすることなく、もう少しシンプルに書くことは可能でしょうか。
どなたかアドバイスをお願いいたします。

data test;
input ID $ NO DAT1 $ TIM1 $ DAT2 $ TIM2 $;
cards;
1	1	2020/8/4	8:30	2020/8/5	8:30
1	2	2020/8/18	8:30	2020/8/19	8:30
1	3	2020/9/1	8:30	2020/9/2	8:30
1	4	2020/9/15	8:30	2020/9/16	8:30
2	1	2020/8/4	8:34	2020/8/5	8:34
2	2	2020/8/18	8:34	2020/8/19	8:34
2	3	2020/9/1	8:34	2020/9/2	8:34
2	4	2020/9/15	8:34	2020/9/16	8:34
3	1	2020/8/4	8:46	2020/8/5	8:46
3	2	2020/8/18	8:46	2020/8/19	8:46
3	3	2020/9/1	8:46	2020/9/2	8:46
3	4	2020/9/15	8:46	2020/9/16	8:46
;
run;

proc sql;
 create table test3 as
 select ID,
        max(case when NO = 1 then DAT1 end) as A1,
        max(case when NO = 2 then DAT1 end) as B1,
        max(case when NO = 3 then DAT1 end) as C1,
        max(case when NO = 4 then DAT1 end) as D1,
        max(case when NO = 1 then TIM1 end) as A2,
        max(case when NO = 2 then TIM1 end) as B2,
        max(case when NO = 3 then TIM1 end) as C2,
        max(case when NO = 4 then TIM1 end) as D2,
        max(case when NO = 1 then DAT2 end) as A3,
        max(case when NO = 2 then DAT2 end) as B3,
        max(case when NO = 3 then DAT2 end) as C3,
        max(case when NO = 4 then DAT2 end) as D3,
        max(case when NO = 1 then TIM2 end) as A4,
        max(case when NO = 2 then TIM2 end) as B4,
        max(case when NO = 3 then TIM2 end) as C4,
        max(case when NO = 4 then TIM2 end) as D4
 from test group by ID;
quit;
proc print data = test3; run;