回答編集履歴
2
追加
test
CHANGED
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@@ -35,3 +35,27 @@
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35
35
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order by 1;
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36
36
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37
37
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```
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38
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+
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39
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+
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40
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+
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41
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+
ちょとわかりずらいですが
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42
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+
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43
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+
```sql
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44
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+
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45
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+
select p.id, p.name, '信長&秀吉'
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46
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+
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47
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from publisher p
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48
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+
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49
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join
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50
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+
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51
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(select distinct b.publisher_id from book b
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52
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53
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join book c on b.publisher_id=c.publisher_id
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54
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55
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and b.name = '信長' and c.name = '秀吉'
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56
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+
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57
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) t1
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58
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+
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59
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on p.id=t1.publisher_id
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60
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+
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61
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```
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1
追加
test
CHANGED
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@@ -13,3 +13,25 @@
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13
13
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order by 1;
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14
14
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15
15
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```
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16
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+
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17
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+
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18
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+
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19
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+
複数存在する事も有りますよね
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20
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21
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22
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23
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```sql
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24
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25
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select p.id, max(p.name), max(b.name), max(c.name)
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26
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+
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27
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from publisher p
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28
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+
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29
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join book b on b.publisher_id = p.id and b.name = '信長'
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30
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+
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31
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join book c on c.publisher_id = p.id and c.name = '秀吉'
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32
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+
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33
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group by 1
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34
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+
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35
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order by 1;
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36
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+
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37
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+
```
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