回答編集履歴
2
追記
test
CHANGED
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@@ -57,3 +57,61 @@
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57
57
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print(count) # {-1: 3, 0: 1, 1: 1, 2: 2}
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58
58
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59
59
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```
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60
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+
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61
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62
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63
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質問修正をうけて
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64
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65
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--
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66
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67
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以下のようにDataFrameに対してループ処理を行えば求めることができます。
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68
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69
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```Python
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70
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71
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import pandas as pd
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72
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73
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74
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75
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df = pd.DataFrame([[2,2,1,-1],[0,1,2,2],[1,0,1,2]],columns=['A','B','C','D'])
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76
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77
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print(df)
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78
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79
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80
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81
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# 行毎のループ
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82
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83
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for idx, row in df.iterrows():
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84
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85
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counter = 0
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86
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87
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# 対象列毎のループ
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88
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89
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for val in row['A':'D']:
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90
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91
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if val <= 0:
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92
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93
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break
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94
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95
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counter += 1
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96
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97
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df.loc[idx,'counter'] = counter
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98
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99
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100
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101
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df['counter'] = df['counter'].astype(int) # float -> int
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102
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103
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print(df)
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104
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105
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"""
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106
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107
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A B C D counter
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108
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109
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0 2 2 1 -1 3
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110
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111
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1 0 1 2 2 0
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112
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113
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2 1 0 1 2 1
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114
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115
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"""
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116
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117
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```
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1
追記
test
CHANGED
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@@ -27,3 +27,33 @@
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27
27
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"""
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28
28
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29
29
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```
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30
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31
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32
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33
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コメントを受けて
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34
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35
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--
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36
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37
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38
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39
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(-1,0,1,2)の出現数を求めたいなら、たとえば以下のようにして得られます。
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40
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41
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```Python
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42
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43
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import pandas as pd
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44
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45
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df = pd.DataFrame({'val':[-1,-1,-1,0,1,2,2]})
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46
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47
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48
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49
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count = {}
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50
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51
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for n in [-1,0,1,2]:
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52
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53
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count[n] = (df['val'] == n).sum()
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54
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55
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56
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57
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print(count) # {-1: 3, 0: 1, 1: 1, 2: 2}
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58
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59
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```
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