回答編集履歴
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追記
test
CHANGED
@@ -25,3 +25,61 @@
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```
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追記
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--
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購入日単位でカウントということは集計が必要になるので、相関サブクエリーの方が効率的です。
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```SQL
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select id,購入日
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,(select count(distinct 購入日)+1 from tbl where id=t1.id and 購入日<t1.購入日) as 累計購入回数
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from tbl as t1
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order by 購入日 ,id
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```
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```DATA
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create table tbl(id int,購入日 date);
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insert into tbl values
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(500,'2001-03-24'),
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(500,'2001-03-24'),
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(500,'2001-03-24'),
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(500,'2001-03-27'),
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(500,'2001-03-27'),
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(500,'2001-03-27'),
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(500,'2001-03-27'),
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(500,'2001-03-27'),
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(500,'2001-03-27'),
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(500,'2001-07-21'),
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(500,'2001-07-29'),
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(500,'2003-04-11'),
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(500,'2004-04-26'),
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(500,'2004-09-25'),
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(500,'2006-02-03')
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;
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```
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追記
test
CHANGED
@@ -6,4 +6,22 @@
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from tbl
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order by 購入日, ID
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```
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```DATA
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create table tbl(id int,購入日 date,unique(id,購入日));
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insert into tbl values
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(500,'2018-04-16'),
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(501,'2018-04-16'),
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(500,'2018-04-17')
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;
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```
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