回答編集履歴
4
コード修正
test
CHANGED
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@@ -58,7 +58,9 @@
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AND r1.res.reservation_date < r2.res.reservation_date
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+
)
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-
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) res ON cos.costomer_id = res.costomer_id
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ORDER BY res.reservation_date DESC
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3
コード修正
test
CHANGED
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@@ -108,7 +108,9 @@
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AND r1.reservation_date < r2.reservation_date
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)
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-
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) res ON cos.costomer_id = res.costomer_id
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)
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2
コード修正
test
CHANGED
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@@ -70,13 +70,15 @@
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```SQL
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-
SELECT cos.*, res.*
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(SELECT cos.*, res.*
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FROM costomer cos
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FROM costomer cos
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INNER JOIN costomer_reservation res ON cos.costomer_id = res.costomer_id
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INNER JOIN costomer_reservation res ON cos.costomer_id = res.costomer_id
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WHERE res.reservation_date >= CURRENT_DATE
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WHERE res.reservation_date >= CURRENT_DATE
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)
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@@ -84,29 +86,31 @@
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SELECT cos.*, res.*
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(SELECT cos.*, res.*
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FROM costomer cos
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FROM costomer cos
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INNER JOIN (
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INNER JOIN (
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SELECT *
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SELECT *
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FROM costomer_reservation r1
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FROM costomer_reservation r1
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WHERE NOT EXISTS (
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WHERE NOT EXISTS (
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SELECT *
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SELECT *
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FROM costomer_reservation r2
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FROM costomer_reservation r2
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WHERE r1.costomer_id = r2.costomer_id
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WHERE r1.costomer_id = r2.costomer_id
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AND r1.reservation_date < CURRENT_DATE
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AND r1.reservation_date < CURRENT_DATE
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AND r1.reservation_date < r2.reservation_date
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AND r1.reservation_date < r2.reservation_date
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110
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) res ON cos.costomer_id = res.costomer_id
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) res ON cos.costomer_id = res.costomer_id
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)
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1
追記
test
CHANGED
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@@ -1 +1,131 @@
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1
1
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1と2で条件がかなり異なるので、多少コードが長くなってもSQLを2つ作ってUNIONで繋げたほうが、メンテナンスがやりやすくなるかも知れませんね。
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###2015/8/12追記
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7
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> 同じ名前の項目があると、取り出せないですよね？
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8
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縦につなげるだけなので、要素数や要素名は普通にSELECTした場合と同じだと思うのですが、
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reservation_dateが2つになるというのはどんな時でしょう？
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抽出条件に従うと
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条件1(と3)を抽出するSQLはこんな感じ
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```SQL
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SELECT cos.*, res.*
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FROM costomer cos
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INNER JOIN costomer_reservation res ON cos.costomer_id = res.costomer_id
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WHERE res.reservation_date >= CURRENT_DATE
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ORDER BY res.reservation_date DESC
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```
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条件2(と3)を抽出するSQLはこんな感じ
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```SQL
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SELECT cos.*, res.*
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FROM costomer cos
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INNER JOIN (
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SELECT *
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FROM costomer_reservation r1
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WHERE NOT EXISTS (
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SELECT *
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FROM costomer_reservation r2
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WHERE r1.costomer_id = r2.costomer_id
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AND r1.reservation_date < CURRENT_DATE
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AND r1.res.reservation_date < r2.res.reservation_date
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) res ON cos.costomer_id = res.costomer_id
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ORDER BY res.reservation_date DESC
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```
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UNIONで繋ぐとこんな感じ
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```SQL
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SELECT cos.*, res.*
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FROM costomer cos
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INNER JOIN costomer_reservation res ON cos.costomer_id = res.costomer_id
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WHERE res.reservation_date >= CURRENT_DATE
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UNION
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SELECT cos.*, res.*
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FROM costomer cos
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INNER JOIN (
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SELECT *
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FROM costomer_reservation r1
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WHERE NOT EXISTS (
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SELECT *
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FROM costomer_reservation r2
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WHERE r1.costomer_id = r2.costomer_id
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AND r1.reservation_date < CURRENT_DATE
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+
AND r1.reservation_date < r2.reservation_date
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+
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+
) res ON cos.costomer_id = res.costomer_id
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112
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ORDER BY res.reservation_date DESC
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```
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要素が同じなら抵抗無く連結できると思います。
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※動作テストはしていないのでエラーがあるかも知れません。
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※フラグやクリニックチェックは条件に無かったので省いています
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※条件2の方は、costomer_idとreservation_dateの2つがまったく同じレコードは無い前提です。
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※条件2の方は相関サブクエリを使っており、レコードが多い場合は別の方法にしないと異様に遅いかも知れません。
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