回答編集履歴
3
追記
test
CHANGED
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@@ -7,3 +7,13 @@
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7
7
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having count(distinct number) !=(select count(distinct number) from sample_table)
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8
8
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9
9
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```
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10
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+
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11
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+
全体の要素数が予め決まっているなら以下のように記述できます。
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12
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+
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13
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+
```SQL
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14
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+
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15
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+
select date FROM sample_table group by date
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16
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+
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17
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+
having count(distinct number) !=3
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18
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+
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19
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+
```
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2
追記
test
CHANGED
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@@ -1,3 +1,5 @@
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1
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+
date別のnumberの要素数と全体での要素数を比較します。
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2
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+
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1
3
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```SQL
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2
4
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3
5
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select date FROM sample_table group by date
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1
修正
test
CHANGED
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@@ -2,6 +2,6 @@
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2
2
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3
3
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select date FROM sample_table group by date
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4
4
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5
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-
having count(distinct number) !=(select count(distinct number) fromsample_table)
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5
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+
having count(distinct number) !=(select count(distinct number) from sample_table)
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6
6
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7
7
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```
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