回答編集履歴
2
誤記修正
test
CHANGED
@@ -54,7 +54,7 @@
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const isLeap=(y)=>{
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-
return (y%400==0)?true:(y%100==0)?
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return (y%400==0)?true:(y%100==0)?false:(y%4==0);
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};
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1
サンプルコードの追加
test
CHANGED
@@ -31,3 +31,89 @@
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5.3の結果と4の結果を比較すれば解が出る。
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### 追記
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javascriptで書いてみたけど、結構めんどくさかった。
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```javascript
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(()=>{
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var isBigTimeLag=(a={year:2018,month:6,day:26,hour:13,minute:3},
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b={year:2018,month:6,day:26,hour:17,minute:53})=>{
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const lag={hour:4,minute:20};
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const isLeap=(y)=>{
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return (y%400==0)?true:(y%100==0)?y:(year%4==0);
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};
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const getDayCountOfLastMonth=(y, m)=>{
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return (m==3)?(isLeap(y)?29:28):((m!=2&&m%5==2)||(m%5==0))?30:31;
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};
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let baseYear = 2000;
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while(baseYear < a.year && baseYear < b.year){ baseYear++; }
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while(baseYear > a.year && baseYear > b.year){ baseYear--; }
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const sumDays=(ymd)=>{
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let day = 0;
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for(let y = baseYear, m = 2; y <= ymd.year; y++,m=1){
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for(; m <= (y==ymd.year?ymd.month:12); m++){
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day += getDayCountOfLastMonth(y, m);
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}
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}
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return day;
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}
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a.day += sumDays(a);
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b.day += sumDays(b);
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if(a.day != b.day){
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[a.hour, b.hour]=[a.hour+(a.day>b.day?(a.day-b.day)*24:0),
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b.hour+(b.day>a.day?(b.day-a.day)*24:0)];
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}
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a.minute += a.hour*60;
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b.minute += b.hour*60;
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let t = lag.hour*60 + lag.minute;
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return (a.minute - b.minute < -1 * t)||(a.minute - b.minute > t);
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};
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console.log(isBigTimeLag());
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})();
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```
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自作することのめんどくささよ。
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