回答編集履歴
2
修正
test
CHANGED
@@ -54,9 +54,11 @@
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54
54
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55
55
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56
56
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57
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+
printf("%s, adress: %p\n", str, str);
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58
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+
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57
59
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for(char *pt = str; *pt != '\0'; pt++) {
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58
60
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59
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-
printf("%c, adress: %p\n", *pt, pt);
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61
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+
printf("%5c, adress: %p\n", *pt, pt);
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60
62
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61
63
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}
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62
64
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@@ -76,15 +78,17 @@
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76
78
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77
79
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```
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78
80
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79
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-
H, adress: 00405064
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81
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+
Hello, adress: 00405064
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80
82
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81
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-
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83
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+
H, adress: 00405064
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82
84
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83
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-
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85
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e, adress: 00405065
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84
86
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85
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-
l, adress: 0040506
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87
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+
l, adress: 00405066
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86
88
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89
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+
l, adress: 00405067
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90
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+
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87
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-
o, adress: 00405068
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91
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o, adress: 00405068
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88
92
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89
93
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```
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90
94
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1
追記
test
CHANGED
@@ -33,3 +33,63 @@
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33
33
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34
34
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35
35
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問題ないです。
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36
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+
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37
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+
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38
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+
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39
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+
追記
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40
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+
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41
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+
---
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42
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+
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43
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```C
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44
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+
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45
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+
#include<stdio.h>
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46
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47
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48
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+
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49
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int main()
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50
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51
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{
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52
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53
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char *str = "Hello";
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54
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55
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+
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56
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+
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57
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+
for(char *pt = str; *pt != '\0'; pt++) {
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58
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+
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59
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+
printf("%c, adress: %p\n", *pt, pt);
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60
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+
|
61
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}
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62
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+
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63
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printf("\n");
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64
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+
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65
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+
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66
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+
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67
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return 0;
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68
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+
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69
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}
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70
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+
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71
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```
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72
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+
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73
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+
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74
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75
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**実行結果**
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76
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+
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77
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```
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78
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+
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79
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+
H, adress: 00405064
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80
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+
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81
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+
e, adress: 00405065
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82
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+
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83
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+
l, adress: 00405066
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84
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+
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85
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+
l, adress: 00405067
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86
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+
|
87
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+
o, adress: 00405068
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88
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+
|
89
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+
```
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90
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+
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91
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+
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92
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+
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93
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**『ヌル終端しているから、先頭の文字のアドレスを文字列のアドレスとみなせる』**んです。
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94
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+
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95
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+
一文字一文字アドレスは別個です。
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