質問編集履歴
3
コード変更
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```
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### 追記1
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選択経路を色を変えて、表現するのは
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``networkx``においてナンセンスだと思い直したので変更
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変更したことで``nx.connected_components(G)``で正しく連結成分を
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利用することができます
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以下のように変更
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* 経路ではないedgeは表示しない
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```python
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import matplotlib.pyplot as plt
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import networkx as nx
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point_num = 3
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line_num = point_num - 1
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edge_num = point_num * line_num * 2
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selected_edges_index = [0,5,10,11]
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G = nx.grid_graph([point_num, point_num])
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edges_copy = list(G.edges)
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pos = dict((n, n) for n in G.nodes())
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nx.draw_networkx_edge_labels(G, pos,{
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edge:i for (i,edge) in enumerate(G.edges) #add number of edge
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})
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G.remove_edges_from(list(G.edges)) # remove all edges
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for i in selected_edges_index:
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G.add_edge(edges_copy[i][0],edges_copy[i][1])
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nx.draw(G,pos,font_size=8)
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#plt.savefig("grid.png")
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plt.show()
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```
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2
解決後 まとめ
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test
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###補足情報(言語/FW/ツール等のバージョンなど)
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python3.6
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###解決後 まとめ
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``networkx``を用いることで容易に経路の図示ができました
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回答して頂いたコードを以下のように変更しました
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* 選択された経路の色を変更
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* 経路の番号の表示
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]
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```python
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import matplotlib.pyplot as plt
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import networkx as nx
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point_num = 3
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line_num = point_num - 1
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G = nx.grid_graph([point_num, point_num])
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pos = dict((n, n) for n in G.nodes())
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edge_num = point_num * line_num * 2
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colors = ['k' for _ in range(edge_num)] # default color is black (k)
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selected_edges_index = [0,5,10,11]
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for index in selected_edges_index:
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colors[index] = 'r' #change edge color to red
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nx.draw_networkx_edge_labels(G, pos,{
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edge:i for (i,edge) in enumerate(G.edges) #add number of edge
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})
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nx.draw(G,pos,edge_color=colors,font_size=8)
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plt.savefig("grid.png")
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```
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1
画像
test
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(番号はついてなくてもいいです）
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