質問編集履歴
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# if x=='user01':if 'id02'==i and y in (2) and Flag in (1):#1
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# if x=='user02':if 'id02'==i and y in (2) and Flag in (
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# if x=='user02':if 'id02'==i and y in (2) and Flag in (0):#0
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if 'id03'==i and y in (2,3):#1
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街コロ
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https://ja.wikipedia.org/wiki/%E8%A1%97%E3%82%B3%E3%83%AD
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上記のテーブルゲームをコンソールで作成してますが、
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誰のターンか判別する仕組みが分かりません。
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コードの中盤にコメントで描いてます。
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```python
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# 0=誰のターンでも可能
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# 1=自分のターン
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# 2=相手のターン Other
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l=[
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# id 購入費用 誰のターン有効か012 出目 報酬
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[['id01'],[999],[0],[1],[1]],#購入不可 全ユーザに初期配置 1coin 1result Anyone 1blessing
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[['id02'],[1],[0],[2],[1]],# 1coin 2result Anyone 1blessing
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[['id03'],[1],[1],[2,3],[1]],# 1coin 2,3result Myself 1blessing
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[['id04'],[2],[2],[3],[1]],# 1coin 1,2,3,4,5,6result Other 1blessing
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[['id05'],[2],[1],[4],[3]],#3coin 4result myself 3blessing
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[['id06'],[3],[0],[5],[1]],#1coin 5result 1blessing
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[['id07'],[5],[1],[7],[3]],#5coin 7result myself id02*3blessing
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[['id08'],[3],[1],[8],[3]],#3coin 8result myself (id06+id09)*3blessing
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[['id09'],[6],[0],[9],[5]],#6coin 9result 5blessing
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[['id10'],[3],[0],[9,10],[2]],#3coin 9,10result 2blessing
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[['id11'],[3],[0],[10],[3]],#3coin 10result 3blessing
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[['id12'],[2],[1],[11,12],[2]],#2coin 11,12result 2blessing (id11+id12)*2blessing
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[['id13'],[6],[1],[6],[2]],#2coin oll 6result 2blessing 全員から
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[['id14'],[6],[1],[6],[5]],#6coin 6result 5blessing 相手指定 5coin貰う
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#[['id15'],[6],[1],[6],['-']],#6coin 6result 建物を1つ交換 未実装
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[['id20'],[4],[1],[0],[0]],#4coin 効果:(常時)ダイスを2個同時に振れる
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[['id21'],[10],[1],[6],[5]],#10coin 効果:(常時)自分の【飲食店】と【商店】で得られるコインを+1する
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[['id22'],[16],[1],[6],[5]],#16coin 効果:(常時)ぞろ目を出したらもう一度自分のターン
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[['id23'],[22],[1],[0],[0]],#22coin 効果:(常時)毎ターン一度だけダイスを振り直せる
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]
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#1,2 user
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user01=[['id01'],[3]]
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user02=[['id01'],[3]]
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import random
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saicoro=random.randint(1,6)
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from pprint import pprint
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#print(l[1][2][0]) # 0
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#print(user01[1][0]) #3
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#print(l[1][0][0]) #id01
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#print(l[1][1][0]) # 1
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# 購入とカードの追加 簡易 後処理必要
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def Sample01_Demo01(x,y):
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try:
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if x[1][0]-l[y][1][0]>=0:
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x[1][0]=x[1][0]-l[y][1][0]
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x[0].append(l[y][0][0])
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except:
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pass
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def Sample01(x):
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#def Sample01_Demo02(x):
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# 購入費用が足りてれば購入 yで継続 Enterでターンエンド
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def Sample01_Demo02(xxx):
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xyz=input()
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try:
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if xyz.isdecimal()==True:
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Sample01_Demo01(xxx,int(xyz))
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print(xxx)
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Bu=input()
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if Bu=='y':
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Sample01_Demo02(xxx)
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else:
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pass
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except TypeError:
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pass
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# x=user01 y=saicoro z=Flag 01
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def Sample01_Demo03(x,y,z):
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for i in x[0]:
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if 'id01'==i:#0
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if 0==x[1][0]:
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x[1][0]+=1
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if 'id02'==i and y in (2):#0
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x[1][0]+=1
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# userによって、自分自身を表す。Flagの値が変化してしまう。
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# if x=='user01':if 'id02'==i and y in (2) and Flag in (1):#1
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# if x=='user02':if 'id02'==i and y in (2) and Flag in (2):#0
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if 'id03'==i and y in (2,3):#1
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x[1][0]+=1
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if 'id04'==i and y in (3):#2
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x[1][0]+=1
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if 'id05'==i and y in (4):#1
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x[1][0]+=3
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if 'id06'==i and y in (5):#0
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x[1][0]+=1
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if 'id07'==i and y in (7):#1
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x[1][0]+=3
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if 'id08'==i and y in (8):#1
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x[1][0]+=3
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if 'id09'==i and y in (9):#1
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x[1][0]+=5
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if 'id10'==i and y in (9,10):#2
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x[1][0]+=2
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if 'id11'==i and y in (10):#0
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x[1][0]+=3
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if 'id12'==i and y in (11,12):#1
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x[1][0]+=2
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if 'id13'==i and y in (6):#
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x[1][0]+=2
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if 'id14'==i and y in (6):#
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x[1][0]+=5
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if 'id20'==i and y in (6):#
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pass
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if 'id21'==i and y in (0):#
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x[1][0]+=5
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if 'id22'==i and y in (6):#
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x[1][0]+=5
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if 'id23'==i and y in (0):#
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pass
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print(i)
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Flag=1
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Sample01_Demo03(user01,saicoro,Flag%2)
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"""
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print('1から17を入力してカードを購入')
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print('購入を続けるなら、yを入力')
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print('Enterでターン終了')
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Flag=0
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while 1:
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Flag+=1
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if
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if Flag%2==1:
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print('user01')
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Sample01_Demo02(user01)
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saicoro=random.randint(1,6)
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Sample01_Demo03(user01,saicoro,Flag%2)
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elif
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elif Flag%2==0:
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print('user02')
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Sample01_Demo02(user02)
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saicoro=random.randint(1,6)
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Sample01_Demo03(user02,saicoro,Flag$2)
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if Flag%2==1:
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"""
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Sample01(int(Flag%2))
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print(Flag%2)
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elif Flag%2==0:
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#print('user02')
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Sample01(int(Flag%2))
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print(Flag%2)
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if Flag==5:
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break
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```
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#
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-
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サンプルでは、Flagの0と1でユーザーを判別してますが、
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ユーザー1が選択された時やユーザー2が選択された時に、自分自身=1
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として扱う方法は無いでしょうか?
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関数内にif文を書き込むとコード量が2倍になってしまいます。
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