質問編集履歴
2
誤字
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サンプルソースでは、close()ような指示がけれど、
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サンプルソースでは、close()ような指示が書いていないけれど、
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close(),exit()ような処理が必要ですか。
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文法の修正
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#1質問内容を修正しました
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まだまだ独学中のメガネです。
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https://qiita.com/code_monkey/items/0d38a92a2a2026f5ec82
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上記のサイトを参考して、urlは表示できました、そのあとに
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Traceback (most recent call last):
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File "C:\Users\Ohcpin-Private\Desktop\Google.py", line 14, in <module>
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main()
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File "C:\Users\Ohcpin-Private\Desktop\Google.py", line 11, in main
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google_search("神威 意味")
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File "C:\Users\Ohcpin-Private\Desktop\Google.py", line 6, in google_search
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for url in search(query,lang= 'jp',num=limit):
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File "C:\Program Files (x86)\Python37-32\lib\site-packages\googlesearch\__init__.py", line 359, in search
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html = get_page(url)
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File "C:\Program Files (x86)\Python37-32\lib\site-packages\googlesearch\__init__.py", line 147, in get_page
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response = urlopen(request)
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File "C:\Program Files (x86)\Python37-32\lib\urllib\request.py", line 222, in urlopen
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return opener.open(url, data, timeout)
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File "C:\Program Files (x86)\Python37-32\lib\urllib\request.py", line 531, in open
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response = meth(req, response)
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File "C:\Program Files (x86)\Python37-32\lib\urllib\request.py", line 641, in http_response
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'http', request, response, code, msg, hdrs)
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File "C:\Program Files (x86)\Python37-32\lib\urllib\request.py", line 563, in error
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result = self._call_chain(*args)
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File "C:\Program Files (x86)\Python37-32\lib\urllib\request.py", line 503, in _call_chain
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result = func(*args)
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File "C:\Program Files (x86)\Python37-32\lib\urllib\request.py", line 755, in http_error_302
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return self.parent.open(new, timeout=req.timeout)
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File "C:\Program Files (x86)\Python37-32\lib\urllib\request.py", line 531, in open
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response = meth(req, response)
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File "C:\Program Files (x86)\Python37-32\lib\urllib\request.py", line 641, in http_response
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'http', request, response, code, msg, hdrs)
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File "C:\Program Files (x86)\Python37-32\lib\urllib\request.py", line 569, in error
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return self._call_chain(*args)
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File "C:\Program Files (x86)\Python37-32\lib\urllib\request.py", line 503, in _call_chain
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result = func(*args)
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File "C:\Program Files (x86)\Python37-32\lib\urllib\request.py", line 649, in http_error_default
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raise HTTPError(req.full_url, code, msg, hdrs, fp)
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urllib.error.HTTPError: HTTP Error 503: Service Unavailabl
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のエラーが出てきていました。
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-
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113
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サンプルソースでは、close()ような指示がけれど、
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42
114
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43
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-
close(),exit()
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115
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+
close(),exit()ような処理が必要ですか。
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+
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ブラウザで検索なら、問題がないけれど、この.pyだけ実行すると、この問題が発生しました。
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