PHP mySQL 名前習得

以下のコードにて自身のフォルダ(Test)に保存された test.img のファイル名や拡張子などを取得しSQLに保存するにはどうすればよいのでしょうか

PHP
1  try {  
2    	$dbh = new PDO('mysql:host=localhost;dbname=imagedb', 'root', '');
3      $sql = "INSERT INTO images (
4      		id, title, description, userId,extention
5      	) VALUES (
6      　　'1',
7          '2',
8          '3',
9          '4',
10          '5'
11      	)";
12      	$res = $dbh->query($sql);
13      } catch(PDOException $e) {
14      	echo $e->getMessage();
15      	die();
16      }
17      $dbh = null;

//PHP　全文
<!DOCTYPE html>
<html lang ="en">

<body>
<form enctype="multipart/form-data" method="POST" action="index.php">
<input type ="file" name ="userfile">
<input type = "submit" value="upload">

<form action = "kensaku,php" method="post">
タイトル：<input type="text" name="nm">
<input type="submit" name="exec" value="検索">

</form>

<?php
if(isset($_FILES["userfile"]) and $_FILES["userfile"]["error"]==0){

  $uploadDir = './userid/';
  $uploadPath = $uploadDir . $_FILES['userfile']['name'];

if(!isset($_POST['submit'])){
  if(move_uploaded_file(
    $_FILES['userfile']['tmp_name'],
    $uploadPath
  )){
    echo '成功です';

    echo $uploadPath = __FILE__;
    echo $title = basename($uploadPath);

    try {
    	$dbh = new PDO('mysql:host=localhost;dbname=imagedb', 'root', '');
      $sql = "INSERT INTO images (
          id, title, description, userId,extention
        ) VALUES (
          '$uploadPath',
          '$title',
          'description',
          'userId',
          'extention'
        )";

      	$res = $dbh->query($sql);
      } catch(PDOException $e) {
      	echo $e->getMessage();
      	die();
      }
      $dbh = null;
  }else{
    echo '失敗です';
  }
}
}
echo "<br />\n";

$dir_path = './userid/';
if (is_dir($dir_path)){
if(is_readable($dir_path)){
$ch_dir = dir($dir_path);

while (false !== ($file_name = $ch_dir -> read())){
$ln_path = $ch_dir -> path . "/" .$file_name;

if (@getimagesize($ln_path)){

  echo "<a href = \"imgview.php?d=" .urlencode(mb_convert_encoding($ln_path, "UTF-8")). "\" target = \"_blank\" >";
  echo "<img src = \"" .$ln_path. "\" width=\"100\"></a> ";

}}
$ch_dir -> close();}
else{
echo "<p>" .htmlspecialchars($dir_path)."　は読み込みが許可されていません。";}}
else{
echo 'DIR 画像がないよ';}

?>

</body>
</html>